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dedylja [7]
3 years ago
8

Pls help meeee the question is in the photo pls no links or fake answers pls answer both questions

Mathematics
1 answer:
maria [59]3 years ago
8 0

Answer:

Step-by-step explanation:

First one is TRUE...you'd multiply by <u>negative</u> one third

Second is FALSE...no multiplication needed to get x as a positive.

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5x - 2 = 10 - X<br> Please help
finlep [7]

Answer:

x = 2

Step-by-step explanation:

5x - 2 = 10 - x

<em>Add x to both sides</em>

6x - 2 = 10

<em>Add 2 to both sides</em>

6x = 12

<em>Divide both sides by 6</em>

x = 2

3 0
3 years ago
If segment AB is 4 units, segment AD is 23 units, and segment CD is 12 units, what is the length of segment BC?
Thepotemich [5.8K]

Answer:

<h2>C . 7 units</h2>

Step-by-step explanation:

The question is lacking appropriate diagram. Find the diagram to the question attached.

From the diagram, it can be seen that AD = AB+BC+CD

Given the following

AD = 23units

AB = 4units

CD = 12units

To get C=BC, we will substitute the given segments into the expression above as shown;

23 = 4+BC+12

23 = BC + 4 + 12

23 = BC+16

Subtract 16 from both sides

23-16 = BC+16-16

7 = BC

<em></em>

<em>Hence the length of segment BC is 7units.</em>

3 0
3 years ago
What number is 2% of 35
n200080 [17]
The answer is 0.7                     :)
7 0
3 years ago
Read 2 more answers
Please help solve the equation using cos(no links)
Alex777 [14]

Answer:

cos 52 = 11/alpha ---> alpha = 11/cos52 = 17.9

5 0
3 years ago
A homeowner plans to enclose a 200 square foot rectangular playground in his garden, with one side along the boundary of his pro
Anestetic [448]

Answer:

Therefore the length and width of the playground are 15.5 feet and 12.9 feet respectively.

Step-by-step explanation:

Given that, a homeowner plans to enclose a 200 square foot rectangle playground.

Let the width of the playground be y and the length of the  playground be x which is the side along the boundary.

The perimeter of the playground is = 2(length +width)

                                                          =2(x+y) foot

The material costs $1 per foot.

Therefore total cost to give boundary of the play ground

=$[ 2(x+y)×1]    

=$[2(x+y)]  

But the neighbor will play one third of the side x foot.

So the neighbor will play  =\$(\frac13x)

Now homeowner's total cost for the material is

=\$[ 2(x+y)-\frac13x]

=\$[2x+2y-\frac13x]

=\$[2y+x+x-\frac13x]

=\$[2y+x+\frac{3x-x}{3}]

=\$[2y+x+\frac{2}{3}x]

=\$[2y+\frac53x]

\therefore C(x)=2y+\frac53x  

where C(x) is total cost of material in $.

Given that the area of the playground is 200.

We know that,

The area of a rectangle is =length×width

                                           =xy square foot

∴xy=200

\Rightarrow y=\frac{200}{x}

Putting the value of y in C(x)

\therefore C(x)=2(\frac{200}{x})+\frac53x

The domain of C is(0,\infty ).

\therefore C(x)=2(\frac{200}{x})+\frac53x

Differentiating with respect to x

C'(x)= - \frac{400}{x^2}+\frac53

Again differentiating with respect to x

C''(x) = \frac{800}{x^3}

To find the critical point set C'(x)=0

\therefore 0= - \frac{400}{x^2}+\frac53

\Rightarrow \frac{400}{x^2}=\frac{5}{3}

\Rightarrow x^2 =\frac{400\times 3}{5}

\Rightarrow x=\sqrt{240}

\Rightarrow x=15.49 \approx15.5

Therefore

\left C''(x) \right|_{x=15.5}=\frac{800}{15.5^3}>0

Therefore at x= 15.5 , C(x) is minimum.

Putting the value of x in y=\frac{200}{x} we get

\therefore y=\frac{200}{15.5}

    =12.9

Therefore the length and width of the playground are 15.5 feet and 12.9 feet respectively.

                                             

6 0
3 years ago
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