Answer:
4 a+8 ab+8b
Step-by-step explanation:
8 a-4 a+6ab+2ab+5 b+3 b
4 a+8 ab+8b
3(x−5)/2=2(x+5)/3
Cross-multiply.
(3(x−5))/2=(2(x+5))/3
3(x−5)*(3)=2(x+5)*(2)
9x−45=4x+20
Subtract 4x from both sides.
9x−45−4x=4x+20−4x
5x−45=20
Add 45 to both sides.
5x−45+45=20+45
5x=65
Divide both sides by 5.
5x/5=65/5
x=13
Answer: 12
Step-by-step explanation:
I will assume those are coordinates.
The distance between 2 points is given by √ (x2 − x1)^2 + (y2 − y1)^2.
Replacing the values, we get √ (5 − 5)^2 + (6 − -6)^2 = √0+144 = 12
Answer:
49/8 is the value of k
Step-by-step explanation:
We have the system
x = -2y^2 - 3y + 5
x=k
We want to find k such that the system intersects once.
If we substitute the second into the first giving us k=-2y^2-3y+5 we should see we have a quadratic equation in terms of variable y.
This equation has one solution when it's discriminant is 0.
Let's first rewrite the equation in standard form.
Subtracting k on both sides gives
0=-2y^2-3y+5-k
The discriminant can be found by evaluating
b^2-4ac.
Upon comparing 0=-2y^2-3y+5-k to 0=ax^2+bx+c, we see that
a=-2, b=-3, and c=5-k.
So we want to solve the following equation for k:
(-3)^2-4(-2)(5-k)=0
9+8(5-k)=0
Distribute:
9+40-8k=0
49-8k=0
Add 8k on both sides:
49=8k
Divide both sides by 8"
49/8=k
Answer:
It is actually less than 10.
Step-by-step explanation:
