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kykrilka [37]
3 years ago
12

Is 3 a factor of 12 yes or no

Mathematics
2 answers:
Leokris [45]3 years ago
5 0

Answer:

Step-by-step explanation:

Yes, 3 is a factor of 12

because : 12=3×4

FinnZ [79.3K]3 years ago
4 0

Answer:

Yes

Step-by-step explanation:

Yes, 3 is a factor of 12.

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The answer is 15 cookies and 5 brownies

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A system of two linear equations and three unknowns can be solved by:
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These cannot be solved.- 3 unknowns require 3 equations 
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3 years ago
F^-1(-10) + f(-6) <br> Please help!!!!
Brums [2.3K]

Answer:

-10/f-6f

Step-by-step explanation:

simplify it the equation

4 0
3 years ago
A right circular cylinder has a height of 22 1/4 ft and a diameter 2 2/5 times its height. What is the volume of the cylinder? E
Triss [41]

Answer:

The volume of cylinder is:

49806.06 ft^3

Step-by-step explanation:

We are given a right circular cylinder with:

Height(h)=22\frac{1}{4}ft=\dfrac{89}{4}ft

and a diameter is 2\frac{2}{5} times it's height.

i.e. \dfrac{12}{5} times it height.

i.e. the diameter is given as:

\dfrac{12}{5}\times \dfrac{89}{4}=\dfrac{267}{5}ft.

We know that the radius of cylinder is half the diameter.

Hence, radius(r) of cylinder is:

\dfrac{1}{2}\times \dfrac{267}{5}\\\\=\dfrac{267}{10}

The volume(V) of cylinder is given by:

V=\pi r^2h

V=3.14\times (\dfrac{267}{10})^2\times \dfrac{89}{4}\\\\V=\dfrac{19922423.94}{400}\\\\V=49806.06ft^3

Hence, the volume of cylinder is:

49806.06 ft^3

7 0
3 years ago
Hi i just need help checking if my answer is correct I have been working on a implicit diffrention problem and I need some help.
SSSSS [86.1K]

Answer:

  \dfrac{dy}{dx}=\dfrac{-4x^3y+2y^3+3x^2y^3}{x^4-6xy^2-3x^3y^2}

Step-by-step explanation:

Normally, when I do this, I differentiate each term first with respect to x then with respect to y. In this solution, I differentiated the entire expression with respect to x, then with respect to y. That makes separating the dx and dy coefficients much easier, so the solution almost falls into your lap.

  -x^4 y + 2 x y^3 + x^3 y^3=0 \qquad\text{given}\\\\(-4x^3y+2y^3+3x^2y^3)dx+(-x^4+6xy^2+3x^3y^2)dy=0\\\\(-4x^3y+2y^3+3x^2y^3)dx=(x^4-6xy^2-3x^3y^2)dy\\\\\boxed{\dfrac{dy}{dx}=\dfrac{-4x^3y+2y^3+3x^2y^3}{x^4-6xy^2-3x^3y^2}}

6 0
2 years ago
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