The sum of squares of numbers is: 13
Step-by-step explanation:
Let x and y be two numbers
Then,
Difference of the squares of the numbers will be:

Product will be:

Given identity is:

Given values are:
Difference of the squares of the numbers=
Product of numbers = xy = 6
Putting the values in the identity
![(x^2+y^2)^2=(5)^2+[2(6)]^2\\=25+(12)^2\\=25+144\\=169](https://tex.z-dn.net/?f=%28x%5E2%2By%5E2%29%5E2%3D%285%29%5E2%2B%5B2%286%29%5D%5E2%5C%5C%3D25%2B%2812%29%5E2%5C%5C%3D25%2B144%5C%5C%3D169)
As we have to only find x^2+y^2
Taking square root on both sides

The sum of squares of numbers is: 13
Keywords: Identities
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Answer:
No extraneous solution
Step-by-step explanation:
We have the logarithmic equation given by,
![\log_{2}[\log_{2}(\sqrt{4x})]=1](https://tex.z-dn.net/?f=%5Clog_%7B2%7D%5B%5Clog_%7B2%7D%28%5Csqrt%7B4x%7D%29%5D%3D1)
i.e. 
i.e. 
i.e. 
i.e. 
i.e. 
i.e. 
So, the solution of the given equation is x=4.
Now, as we domain of square root function is x > 0 and also, the domain of logarithmic function is
.
Therefore, the domain of the given function is x > 0.
We know that the extraneous solution is the solution which does not belong to the domain.
But as x=4 belongs to the domain x > 0.
Thus, x = 4 is not an extraneous solution.
Hence, this equation does not have any extraneous solution.
There are two pints in a quart
so 3 times 2 equals 6
3 qt = 6 pt
Answer:
Step-by-step explanation:
Given that:
sin2xcos x + cos2xsin x = -1
Recall that;
SInAcosB + cosASinB = SIn (A+B)
SIn (2x +x) = -1
Sin (3x) = -1
![x = \bigg [\dfrac{Sin ^{-1} (-1)}{3} \bigg ]](https://tex.z-dn.net/?f=x%20%3D%20%5Cbigg%20%5B%5Cdfrac%7BSin%20%5E%7B-1%7D%20%28-1%29%7D%7B3%7D%20%20%5Cbigg%20%5D)


26 because 5 gose in to 13 2 times and you have 3 left bring down the zero for 30 and 6 gose in to it evenly