Answer:
Here,
First Find distance between them by using formula √+x2-x1)2+(y2-y1)2
Then use the equation and then find locus.
Y = x^2 + 2x - 1 = x^2 + 2x + 1 - 1 - 1 = (x + 1)^2 - 2
The vertex of a parabola given by y = a(x - h)^2 + k is (h, k).
Therefore, the vertex of y = (x + 1)^2 - 2 is (-1, -2)
Answer: Yes they could.
Step-by-step explanation:
The two pairs of sides given are proportional: 3/7 : 9/21
The two triangles have the side:side ratio, meaning they are similar
Because they are similar, their hypotenuses <em>could</em> lie along the same line, not guaranteed, but possible.
Mult 2 by x you'll get 2x then 2 by 3 you'll get 6 and add 6 to 5, after that you'll get 11 it should look like this 2x+11.
