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skad [1K]
3 years ago
15

Given that tan theta = square root of 3 over 4, and 0 < theta < pi over 2, what is the exact value of cot theta?

Mathematics
1 answer:
Natali5045456 [20]3 years ago
5 0

Answer:

\frac{4\sqrt{3} }{3}

Step-by-step explanation:

4sqrt3/3

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What is 1.83 repeating as a fraction?
maks197457 [2]
The answer to this question would be: 1 5/6

To change a decimal number into fraction, you need to divide the number on the right of decimal point with 1. In this case, the number is 0.83.
This number is hard since .83 doesn't have many factors. To find the answer you can try to multiply the decimal with some number until it close to 1(no decimal left)
0.83* 2= 1.66
0.83* 3= 2.49 ---> close to half, if you find this number, you can try to double it
0.83* 4= 3.32
0.83* 5= 4.15
0.83* 6= 4.98---> close to 1, that means there is high probability that the number can be divided by 6 
0.83 would be 4.98/6, but if we assume that the number is 0.8333...... then 0.83 would be 5/6. So, 1.83 would be 1 5/6
4 0
3 years ago
Read 2 more answers
I got 1.1... is that right?
kap26 [50]

No, the answer is 2

X=2

This is because if we multiply the number by x which is 2

so DST is 110, and RSD is 44, so that is 154, and if we do it with RST we also get 154

So the correct answer is X=2

3 0
3 years ago
Which best explains whether a triangle with side lengths 2in , 5in , 4in. is an acute triangle
lutik1710 [3]
So we know that 3,4 and 5 are pythagorean triplet and these result from a right triangle sides length 
- than 3,4 and 5 mean right triangle so 2,5 and 4 mean acute triangle sure or you can prove it in this way too
- than 3^2 +4^2 =5^2 => a right triangle so than 
2^2 +4^2 < 5^2 => an acute triangle 

hope helped 
3 0
3 years ago
Find the measure of
Goryan [66]
What are you talking about
5 0
2 years ago
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Find X and y<br><br> 12, 16
zavuch27 [327]

Answer:

  • x = 6√2
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Step-by-step explanation:

The triangles are all similar, so corresponding sides are proportional.

__

<h3>x</h3>

  long side/short side = x/6 = 12/x

  x² = 72 . . . . . . . multiply by 6x

  x = 6√2 . . . . . . take the square root

__

<h3>y</h3>

  hypotenuse/long side = y/12 = (12+6)/y

  y² = 216 . . . . . multiply by 12y

  y = 6√6 . . . . . take the square root

8 0
2 years ago
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