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3 years ago

-1/2 + (3/4 x 4/9) =

Mathematics

1 answer:

Nookie1986 [14]3 years ago

7 0

-.1666667
You can use khan academy or Socratic if you still not sure.

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The path of a punted football is given by the function: f(x) = (-16/1225)x^2 + (7/5)x + 2.5 where f(x) is the height (in feet) a

nadezda [96]

<span>To find the length of the punt, we equate the expression to zero i.e. f(x) = 0 ,Given, f(x) is the height (in feet) and x is the horizontal distance (in feet) from the point at which the ball is punted. or (-16/1225)x^2 + (7/5)x + 2.5 = 0. On solving for x we get, x = 108 ft.</span>

3 0

3 years ago

Is anyone able to give a step by step process to this?

Thepotemich [5.8K]

Answer:

The value of y is 3 cm.

Step-by-step explanation:

Given,

Perimeter of triangle = $29\ cm$

Solution,

Lets redraw the triangle with nomenclature ABC, given in the attachment.

∴P(ΔABC) = 29 cm (P stands for perimeter)

Length of AB = $y+9$

Length of BC = $2y$

Length of CA = $4y-1$

Now, we all know that the perimeter of a triangle is sum of all the three sides of triangle.

P(ΔABC) = Length of AB+Length of BC+Length of CA

On substituting the values, we get;

$(y+9)+2y+(4y-1)=29\\y+2y+4y+9-1=29\\7y+8=29\\7y=29-8\\7y=21\\y=\frac{21}{7} =3\ cm$

Length of AB = $y+9=3+9=12\ cm$

Length of BC = $2y=2\times3=6\ cm$

Length of CA = $4y-1=4\times3-1=12-1=11\ cm$

Hence the value of y is 3 cm.

8 0

3 years ago

What is the equation of the line passing through the points (2, -1) and (5, -10) in slope intercept form

Nitella [24]

Answer:

-3x+5

Step-by-step explanation:

y2-y1/x2-x1

3 0

3 years ago

I need help so bad does anyone know this

KATRIN_1 [288]

Answer: line C is the correct answer. please mark brainliest

Step-by-step explanation:

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3 years ago

A chemical company makes two brands of antifreeze. The first brand is 65% pure antifreeze, and the second brand is 90% pure anti

Brums [2.3K]

$\bf \begin{array}{lcccl} &\stackrel{solution}{gallons}&\stackrel{\textit{\% of }}{antifreeze}&\stackrel{\textit{gallons of }}{antifreeze}\\ \cline{2-4}&\\ \textit{1st brand}&x&0.65&0.65x\\ \textit{2nd brand}&y&0.90&0.9y\\ \cline{2-4}&\\ mixture&40&0.8&32 \end{array}~\hfill \to \begin{cases} x+y&=40\\ \boxed{x}=40-y\\ \cline{1-2} 0.65x+0.9y&=32 \end{cases} \\\\[-0.35em] ~\dotfill$

$\bf \stackrel{\textit{substituting in the 2nd equation}}{0.65\left( \boxed{40-y} \right)+0.9y=32}\implies 26-0.65y+0.9y=32 \\\\\\ 26+0.25y=32\implies 0.25y=6\implies y=\cfrac{6}{0.25}\implies \blacktriangleright y=24 \blacktriangleleft \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{since we know that}}{x=40-y\implies }x=40-24\implies \blacktriangleright x=16 \blacktriangleleft$

7 0

3 years ago

Read 2 more answers