Given rational expression is
Now we need to find the restricted values if any for this rational expression.
Restricted values means the possible values of the used variable (x) that will make denominator 0 as division by 0 is not defined.
So to find the restricted values, we just set denominator equal to 0 and solve for x
2x=0 or 4x+1=0
x=0 or 4x=-1
x=0 or x=-1/4
Hence final answer is x=0, -1/4
871 miles ........... 13 hours
469 miles ............x hours
x = 469×13/871 = 7 hours
<span>There are 4 EQUAL pieces.
To build 1 whole you must add together 4 pieces or compose the fraction with all four pieces 1/4 + 1/4 + 1/4 + 1/4 = 4/4 or 1 whole.</span>
Options A,B and D. The correction about the area of the triangle are
- The apothem can be found using the Pythagorean theorem.
- The apothem can be found using the tangent ratio.
- The length of the apothem is approximately 2.5 cm.
<h3>How to solve for the length of the Apothem using the Pythagoras theorem</h3>
Firstly this is an equilateral triangle
3 of the sides have the length of 8.7cm
b = half of 8.7
= 4.35cm
To get A we have
a² + b² = c²
a² + 4.35² = 5²
When we solve this out we would have
a² = 25 - 18.9225
a ≈ 2.5 cm.
Hence we have proved that the first option is correct.
<u>For B,</u>
In an equilateral triangles, each of the angles = 60 degrees
60/2 = 30 is the angle that is made from the base
<h3>using tangent ratios </h3>
a / 4.35 = tan 30
then a = 4.35 tan 30
This would also give us an approximate of 2.5
For D
The calculations we have done based on the statements in A and B shows that D is correct as 2.5.
Read more on triangles here:
brainly.com/question/18404158
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The width (W) of the prism is 16 cm.
The length (L) of the prism is 16 cm.
The height (H) of the prism is 10 cm.
The formula for the surface area of any right prism with width W, length L, and height H is the following:
A = 2 (WL + LH + WH)
Substituting using our given values changes the equation to:
A = 2 (16*16 + 16*10 + 16*10)
= 2 (256 + 160 + 160) = 2 (576)
= 1152
Thus, the surface area is 1152 cm².
Let me know if you need any clarifications, thanks!