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3 years ago

Graphing Natural Exponential Functions In Exercise, sketch the graph of the function.

Mathematics

1 answer:

Mnenie [13.5K]3 years ago

3 0

Answer:

Let $g(x)=e^{2x-1}$

View Graph

Step-by-step explanation:

Let $g(x)=e^{2x-1}$

find the cutting points with respect to the axes.

We can say that g(x) = y, well then $y=e^{2x-1}$ , if x=0 then $y=e^{2x-1}=e^{(2*0-1)}=e^{-1}=0.36787$

with respect to x there are no cut points since it is an asymptote

To x=1 y≅2.718, x=-1 y≅0.049, x=2 y≅20.08, x=-2 y≅0.0067, this for plotting some values

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Solve the triangle, AMDM

krok68 [10]

Answer:

Step-by-step explanation:

You are given two sides and the included angle, so you need to use the law of cosines.

c² = a² + b² - 2ab cos C

c² = 12² + 13² - 2(12)(13)cos 134°

c² = 313 - 312(-0.6947)

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2 years ago

Factor completely 64x2 − 49. (1 point)

Roman55 [17]

Answer:

(8x-7)(8x+7)

Step-by-step explanation:

This is a difference of squares polynomial of the form $a^2-b^2=(a+b)(a-b)$ . Since 64 and 9 are both perfect squares then take the square root of each so a=8 and b=7.

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6 0

3 years ago

Engineers must consider the breadths of male heads when designing helmets. The company researchers have determined that the popu

tia_tia [17]

Answer:

The minimum head breadth that will fit the clientele is 4.4 inches.

The maximum head breadth that will fit the clientele is 7.8 inches.

Step-by-step explanation:

Let X = head breadths of men that is considered for the helmets.

The random variable X is normally distributed with mean, μ = 6.1 and standard deviation, σ = 1.

To compute the probability of a normal distribution we first need to convert the raw scores to z-scores using the formula:

$z=\frac{x-\mu}{\sigma}$

It is provided that the helmets will be designed to fit all men except those with head breadths that are in the smallest 4.3% or largest 4.3%.

Compute the minimum head breadth that will fit the clientele as follows:

P (X < x) = 0.043

⇒ P (Z < z) = 0.043

The value of z for this probability is:

z = -1.717

*Use a z-table.

Compute the value of x as follows:

$z=\frac{x-\mu}{\sigma}\\-1.717=\frac{x-6.1}{1}\\x=6.1-(1.717\times 1)\\x=4.383\\x\approx4.4$

Thus, the minimum head breadth that will fit the clientele is 4.4 inches.

Compute the maximum head breadth that will fit the clientele as follows:

P (X > x) = 0.043

⇒ P (Z > z) = 0.043

⇒ P (Z < z) = 1 - 0.043

⇒ P (Z < z) = 0.957

The value of z for this probability is:

z = 1.717

*Use a z-table.

Compute the value of x as follows:

$z=\frac{x-\mu}{\sigma}\\1.717=\frac{x-6.1}{1}\\x=6.1+(1.717\times 1)\\x=7.817\\x\approx7.8$

Thus, the maximum head breadth that will fit the clientele is 7.8 inches.

5 0

3 years ago