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OverLord2011 [107]
3 years ago
14

Solve the right triangle. Give angles in degrees and minutes.

Mathematics
1 answer:
Bess [88]3 years ago
3 0

Answer:

Option A

m\angle B=56.7^o

a=2.5\ m

c=4.5\ m

Step-by-step explanation:

step 1

Find the measure of angle B

we know that

m\angle A+m\angle B=90^o ----> by complementary angles

we have

m\angle A=33.3^o

substitute

33.3^o+m\angle B=90^o

m\angle B=90^o-33.3^o

m\angle B=56.7^o

step 2

Find the measure of side c

Applying the law of sines

\frac{b}{sin(B)}=\frac{c}{sin(C)}

we have

b=3.8\ m\\B=56.7^o\\C=90^o

substitute

\frac{3.8}{sin(56.7^o)}=\frac{c}{sin(90^o)}

c=\frac{3.8}{sin(56.7^o)}sin(90^o)

c=4.5\ m

step 3

Find the measure of side a

Applying the law of sines

\frac{b}{sin(B)}=\frac{a}{sin(A)}

we have

b=3.8\ m\\B=56.7^o\\A=33.3^o

substitute

\frac{3.8}{sin(56.7^o)}=\frac{a}{sin(33.3^o)}

a=\frac{3.8}{sin(56.7^o)}sin(33.3^o)

a=2.5\ m

Note: (mc) is not a unit, in the question the options were written without leaving any space

so

B = 56.7◦; a = 2.5mc = 4.5m

instead of

B = 56.7◦; a = 2.5 m; c=4.5 m

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