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Furkat [3]
2 years ago
13

Find the volume of a pyramid with a square base, where the area of the base is 11.9\text{ in}^211.9 in ​2 ​​ and the height of t

he pyramid is 13.9\text{ in}13.9 in. round your answer to the nearest tenth of a cubic inch.
Mathematics
1 answer:
Lubov Fominskaja [6]2 years ago
3 0

Answer:

The volume of the pyramid is 165.4 inches^3

Step-by-step explanation:

In this question, we are asked to calculate the volume of the pyramid with a square base and also with the given height.

To find the area of this pyramid, what we need to do is to multiply the area of the base by the height of the pyramid

From the question, the area of the square base is 11.9 in^2 while the height of the pyramid is 13.9 in

Thus the volume here is simply 11.9 * 13.9 = 165.41 which to the nearest tenth of cubic inch is 165.4 inch^3

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Base angle of an isosceles triangle is 42 degree,find the third angle?
IceJOKER [234]

Answer:

96°

Step-by-step explanation:

the base angles of an isosceles are congruent , both 42°

Then the third angle = 180° - 42° - 42° = 180° - 84° = 96°

7 0
2 years ago
Which system of equations has a solution of approximately (1.8,-0.9)
Solnce55 [7]

Solve the equation systems or set the values x = 1.8 and y = -0.9 on the equation and check the equality.

A.

6x - 5y = 15

L = 6(1.8) - 5(-0.9) = 10.8 + 4.5 = 15.3

R = 15

L ≈ R

x + 2y = 0

L = 1.8 + 2(-0.9) = 1.8 - 1.8 = 0

L = R

B.

4x + 5y = 8

L = 4(1.8) + 5(-0.9) = 7.2 - 4.5 = 2.7

R = 8

L ≠ R

C.

x - 2y = 4

L = 1.8 - 2(-0.9) = 1.8 + 1.8 = 3.6

R = 4

L ≈ R

4x + 5y = 8

L = 4(1.8) + 5(-0.9) = 7.2 - 4.5 = 2.7

R = 8

L ≠ R

D.

6x - 5y = 15

L = 6(1.8) - 5(-0.9) = 10.8 + 4.5 = 15.3

R = 15

L ≈ R

x - 2y = 4

L = 1.8 - 2(-0.9) = 1.8 + 1.8 = 3.6

R = 4

L ≈ R

We have two probability solutions: A and D.

But I think, Your answer is A.

3 0
3 years ago
Read 2 more answers
6(x-2)= -18 find what x equals
KIM [24]

Answer:

-1

Step-by-step explanation:

x-2 = -3

x=-1

answer is negative one

3 0
3 years ago
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I need answers ASAP!!
lesya [120]
What is the question?

7 0
3 years ago
Read 2 more answers
Brian’s school locker has a three-digit combination lock that can be set using the numbers 5 to 9 (including 5 and 9), without r
andreev551 [17]
The possible digits are: 5, 6, 7, 8 and 9. Let's mark the case when the locker code begins with a prime number as A and the case when <span>the locker code is an odd number as B. We have 5 different digits in total, 2 of which are prime (5 and 7).

First propability:
</span>P_A=\frac{2}{5}=40\%
<span>
By knowing that digits don't repeat we can say that code is an odd number in case it ends with 5, 7 or 9 (three of five digits).

Second probability:
</span>P_B=\frac{3}{5}=60\%
5 0
3 years ago
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