5 consecutive even integers: 2n, 2n+2, 2n+4, 2n+6, 2n+8 for any integer n The sum of the two smallest of five consecutive even integers is 50 less than the sum of the other three integers: 2n + 2n+2 = 2n+4 + 2n+6 + 2n+8 - 504n + 2 = 6n -3234 = 2nn = 17 <span>The smallest integer in our sequence is 2n = 2*17 = 34</span> Check:2n + 2n+2 = 2n+4 + 2n+6 + 2n+8 - 5034 + 36 = 38 + 40 + 42 - 5070 = 120 - 5070 = 70
Answer: 7.5
Step-by-step explanation:
Answer:
18
Step-by-step explanation:
53.83 rounds to 54
36.464 rounds to 36
54-46=18
Answer:
53 54 55
Step-by-step explanation:
Consecutive Integers are integers that go one after the other unless explained otherwise, so 53, 54 and 55 add up to 162.
The correct answer here is that the sum has to be 84. This is due to the
fact that 30 + 54 is 84, and the greatest common factor is 6 because
the factors of 30 are 1, 2, 3, 5, 6 , 10, 15, and 54's Factors: 1, 2, 3,
6, 9, 18, 27, and 54, so from this we can see that 6 is the great
common factor.