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3 years ago

Ben played in 1st,2nd and 4th quarters of the game.He sat out the third quarter.What percentage of the game did Ben play?

Mathematics

2 answers:

eduard3 years ago

6 0

It should be 3/4 hope it helps

horsena [70]3 years ago

4 0

It's 3/4th because he played 3 parts of the game

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What is the value of x? Enter your answer in the box. x =

Triss [41]

Answer:

x = 4.1

Step-by-step explanation:

6x-3 + 3x+6 + 5x = 60

14x + 3 = 60

14x = 60 - 3

14x = 57

x = 57/14

x = 4.1

4 0

2 years ago

X-4y-8=6/8+-8y-2y 5y-3(6-7/8)=5x-4y+3

Ivan

First simplify

x-4y-8=3/4-10y
add 10y both sides and add 8
x+6y=8+3/4
times 4 both sides
4x+24y=32+3
4x+24y=35

5y-3(6-7/8)=5x-4y+3
add 4y both sides
9y-3(6-7/8)=5x+3
distribute
9y-18+21/8=5x+3
minus 5x both sides
9y-5x-18+21/8=3
add 18 to both sides and minus 21/8 both sides
9y-5x=21-21/8
times 8 both sides
72y-40x=147
72y-40x=147

so we got

24y+4x=35
72y-40x=147

multiply first equation by -3 and add to 2nd

-72y-12x=-105
72y-40x=147 +
0y-52x=42

-52x=42
divide both sides by -52
x=-21/26
sub back

24y+4x=35
24y+4(-21/26)=35
using math
y=497/312

the solution is
$( \frac{-21}{26}, \frac{497}{312} )$

8 0

2 years ago

Which expression uses the greatest common factor and

Andrews [41]

It’s A
Cuz 16 \ by 2 is 8 and 36/ by 2 is 18

7 0

3 years ago

We know that a triangle with side lengths , , and is a right triangle. Using those side lengths, find the missing triples and x-

Anit [1.1K]

The completed table for the Pythagorean triples are:

$x \text{ value } \text{ Pythagorean triple}\\\text{ } \text{ } \text{ } 3 \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } (6,8,10)\\\text{ } \text{ } \text{ } 4 \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } (8,15,17)$

$\text{ } \text{ } \text{ } 5 \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } (10,24,26)\\\text{ } \text{ } \text{ } 6 \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } (12,35,37)$ .

A trio of positive numbers known as a Pythagorean triple fits into the Pythagoras theorem's formula, which is written as a² + b² = c², where a, b, and c are all positive integers. Here, "a" and "b" make up the other two legs of the right-angled triangle, and "c" serves as the triangle's "hypotenuse," or longest side. In terms of the Pythagorean triples (a, b, c).

In the question, we are given that a triangle with side lengths x² - 1, 2x, x² + 1 is a right triangle, and are asked to fill in the missing table:

$x \text{ value } \text{ Pythagorean triple}\\\text{ } \text{ } \text{ } 3 \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \underline{\text{ }}\\\text{ } \text{ } \text{ } \underline{\text{ }} \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } (8,15,17)\\$

$\text{ } \text{ } \text{ } 5 \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \underline{\text{ }}\\\text{ } \text{ } \text{ } \underline{\text{ }} \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } (12,35,37)$ .

Taking x as 3, and putting in the sides, we get:

x² + 1 = 3² + 1 = 10.

2x = 2*3 = 6.

x² - 1 = 3² - 1 = 8.

Thus, the triplet is 6,8,10.

For the triplet 8,15,17, we get the x value as:

2x = 8,

or, x = 8/2 = 4.

Thus, the x-value for the triplet (8,15,17) is 4.

Taking x as 5, and putting in the sides, we get:

x² + 1 = 5² + 1 = 26.

2x = 2*5 = 10.

x² - 1 = 5² - 1 = 24.

Thus, the triplet is 10,24,26.

For the triplet 12,35,37, we get the x value as:

2x = 12,

or, x = 12/2 = 6.

Thus, the x-value for the triplet (12,35,37) is 6.

Thus, the completed table for the Pythagorean triples are:

Learn more about the Pythagorean triplets at

brainly.com/question/24211694

#SPJ4

The provided question is incomplete. The complete question is:

"We know that a triangle with side lengths x² - 1,2x and x² + 1 is a right triangle. Using those side lengths, find the missing triples and x-values.

Write the triples in parentheses, without spaces between the numbers, and with a comma between numbers. Write the triples in order from least to greatest.

Type the correct answer in each box.

$x \text{ value } \text{ Pythagorean triple}\\\text{ } \text{ } \text{ } 3 \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \underline{\text{ }}\\\text{ } \text{ } \text{ } \underline{\text{ }} \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } (8,15,17)\\$

6 0

1 year ago

Help please, due by midnight

Allushta [10]

Step-by-step explanation:

The second one is the first claim, because it is a traingles and one square.

The third one is the sond claim because they are a part of the rectangular so moving them outside of it would increase the area, I think, if that makes sense.

3 0

3 years ago