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Sergio039 [100]
4 years ago
6

A fourth degree polynomial with five terms could have, at most, how many different linear factors? 2 3 4 5

Mathematics
2 answers:
Leto [7]4 years ago
7 0
The answer would be 4
Kisachek [45]4 years ago
6 0

Answer:

4

Step-by-step explanation:

We are given a polynomial of degree 4 with five terms.

We have to find atmost  number of different linear factors.

Let the polynomial of degree 4 with 5 terms

x^4+bx^3+cx^2+dx+e

It can be written as the product of linear factors

(px-u)(qx-v)(rx-w)(sx-y)

We know that

Number of linear factors=Degree of polynomial

Consider , a quadratic polynomial

x^2+3x+2

(x+2)(x+1)

Degree of polynomial=2

Number of linear factors=2

Degree of polynomial=Number of linear factors

Hence, the polynomial could have atmost different  linear factors=4

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A scatterplot is made of a citys population over time. The equation that approximates the linear relationship between years and
kicyunya [14]

Answer:

on size and t is the number of years since 2000. What is the meaning of the coefficient of t?

Step-by-step explanation:

A scatterplot is made of a citys population over time. The equation that approximates the linear relationship between years and population is p=629t + 150,000 where p

4 0
3 years ago
Please help me! <br> Will give brainlst :)
eduard

Answer:

the answer

Step-by-step explanation:

and solution are

above

7 0
3 years ago
Which point on the graph of g(x)=(1/5)^x? HELPP
Cloud [144]

Answer:

(-1,5) and (3, \frac{1}{125}) are points on the graph

Step-by-step explanation:

Given

g(x) = \frac{1}{5}^x

Required

Determine which point in on the graph

To get which of point A to D is on the graph, we have to plug in their values in the given expression using the format; (x,g(x))

A. (-1,5)

x = -1

Substitute -1 for x in g(x) = \frac{1}{5}^x

g(x) = \frac{1}{5}^{-1}

Convert to index form

g(x) = 1/(\frac{1}{5})

Change / to *

g(x) = 1*(\frac{5}{1})

g(x) = 5

This satisfies (-1,5)

<em>Hence, (-1,5) is on the graph</em>

<em></em>

B. (1,0)

x = 1

Substitute 1 for x

g(x) = \frac{1}{5}^x

g(x) = \frac{1}{5}^1

g(x) = \frac{1}{5}

<em>(1,0) is not on the graph because g(x) is not equal to 0</em>

C. (3, \frac{1}{125})

x = 3

Substitute 3 for x

g(x) = \frac{1}{5}^x

g(x) = \frac{1}{5}^3

Apply law of indices

g(x) = \frac{1}{5} * \frac{1}{5} * \frac{1}{5}

g(x) = \frac{1}{125}

This satisfies (3, \frac{1}{125})

<em>Hence, </em>(3, \frac{1}{125})<em> is on the graph</em>

<em></em>

D.  (-2, \frac{1}{25})

x = -2

Substitute -2 for x

g(x) = \frac{1}{5}^x

g(x) = \frac{1}{5}^{-2}

Convert to index form

g(x) = 1/(\frac{1}{5}^2)

g(x) = 1/(\frac{1}{5}*\frac{1}{5})

g(x) = 1/(\frac{1}{25})

Change / to *

g(x) = 1*(\frac{25}{1})

g(x) = 25

This does not satisfy  (-2, \frac{1}{25})

<em>Hence, </em> (-2, \frac{1}{25})<em> is not on the graph</em>

8 0
4 years ago
10/13 = 8 - 2z/52 Thats the question. Im dyin for help. :)
svp [43]

Answer:

z = 188

Step-by-step explanation:

1. 10/13 = 8 - 2z/52 (simplify - 2z/52)

10/13 = 8 (- 1/26)*z

2. 10/13 = (- 1/26)*z + 8 (flip for ease in solving)

(- 1/26)*z + 8 = 10/13

3. (- 1/26)*z + 8 = 10/13 (inverse: subtract 8 from each side to isolate variable <em>z</em>)

(- 1/26)*z = 10/13 - (8*13)/(1*13)  (common denominator needed for add/subtract)

(- 1/26)*z = - 94/13 (simplify)

4. (- 1/26)*z = - 94/13 (inverse: multiply both sides by -26/1 to isolate variable <em>z</em>)

<h2>z = 188</h2>
3 0
4 years ago
Read 2 more answers
Which expression models the rental cost after n hours?​
Licemer1 [7]
Can you show the models?
7 0
3 years ago
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