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3 years ago

Algebra 2 Common Core

1 answer:

4 0

I don't know what the answer to number 1 is.

2. Center
25x² + 4y² - 50x - 24y - 39 = 0
 25x² + 4y² - 50x - 24y = 39
 25x² - 50x + 4y² - 24y = 39
 25(x² - 2x) + 4(y² - 6y) = 39
25(x² - 2x + 4) + 4(y² - 6y + 9) = 39 + 25(4) + 4(9)
25(x² - 2x + 4) + 4(y² - 6y + 9) = 39 + 100 + 36
25(x² - 2x + 4) + 4(y² - 6y + 9) = 175
 25(x - 2)² + 4(y - 3)² = 175
 175 175 175
 (x - 2)² + 4(y - 3)² = 1
 7 17

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Compute the sales tax on the following transactions. An article retails for $37.50. The city sales tax is 6%, and the federal ex

ratelena [41]

First you must find the rate of both taxes. Since its 8% and 6%, you must add them both together, then divide them by 100.

14/100 = .14

Then for both rates you must add 1 because it is a tax increase.

1 + .14 = 1.14

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$42.75 is the answer.

7 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP 9TH GRADE MATH AND I NEED HELP, 15 POINTS AND BRAINLIST HELPPPP

Sunny_sXe [5.5K]

Answer:

x = 40°

Step-by-step explanation:

Given that ∠SRT ≅ ∠STR

Then ∠STR = 20

∠STR and ∠STU are what you call supplementary angles. This means that the sum of their measurements is equal to 180° because they form a straight line.

So if:

∠STR + ∠STU = 180°

m∠STU = 4x

m∠STR = 20

Then:

4x + 20° = 180°

Now we solve for x:

$4x + 20 = 180\\\\Subtract\;20\;from\;both\;sides\;of\;the\;equation\\\\4x + 20 - 20 = 180 - 20\\4x = 160\\\\Divide\;both\;sides\;of\;the\;equation\;by\;4\\\\\dfrac{4x}{4}=\dfrac{160}{4}\\\\x = 40$

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3 years ago

You have two options for purchasing a car:

konstantin123 [22]

Answer:

opiton 1

Step-by-step explanation:

person obve me is right

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2 years ago

What is the fourth term in the binomial expansion (a+b)^6)

Dafna11 [192]

Answer:

$20a^3b^3$

Step-by-step explanation:

Binomial Series

$(a+b)^n=a^n+\dfrac{n!}{1!(n-1)!}a^{n-1}b+\dfrac{n!}{2!(n-2)!}a^{n-2}b^2+...+\dfrac{n!}{r!(n-r)!}a^{n-r}b^r+...+b^n$

Factorial is denoted by an exclamation mark "!" placed after the number. It means to multiply all whole numbers from the given number down to 1.

Example: 4! = 4 × 3 × 2 × 1

Therefore, the fourth term in the binomial expansion (a + b)⁶ is:

$\implies \dfrac{n!}{3!(n-3)!}a^{n-3}b^3$

$\implies \dfrac{6!}{3!(6-3)!}a^{6-3}b^3$

$\implies \dfrac{6!}{3!3!}a^{3}b^3$

$\implies \left(\dfrac{6 \times 5 \times 4 \times \diagup\!\!\!\!3 \times \diagup\!\!\!\!2 \times \diagup\!\!\!\!1}{3 \times 2 \times 1 \times \diagup\!\!\!\!3 \times \diagup\!\!\!\!2 \times \diagup\!\!\!\!1}\right)a^{3}b^3$

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2 years ago

Are the functions f(x) = (x^2-1)/(x-1) and g(x)= x+1 equal for all x?

Vinvika [58]

$\bf \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-------------------------------\\\\$

$\bf f(x)=\cfrac{x^2-1}{x-1}\implies f(x)=\cfrac{x^2-1^2}{x-1}\implies f(x)=\cfrac{(\underline{x-1})(x+1)}{\underline{x-1}}
\\\\\\
f(x)=x+1\qquad \qquad \qquad \qquad \qquad g(x)=x+1\\\\
-------------------------------\\\\
\textit{they're, kinda, except that, when x = 1}
\\\\\\
g(x)=(1)+1\implies g(x)=2
\\\\\\
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3 years ago