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3 years ago

Hugo and Koby are measuring the heights of plants in biology class.

Mathematics

2 answers:

Verizon [17]3 years ago

3 0

The answers are shorter, higher, 2cm, 15cm, 20% and 15%.

Step-by-step explanation:

Step 1; From the given data Hugo measured his plant higher than its original height. Hugo measured his plant as 12 cm while it was actually 10 cm. So Hugo's measurement was off by 2cm. Hugo's percent error is given by dividing the difference in values by the actual value.= multiplied by 100.

% error = (difference in values / actual value) × 100

Hugo's % error = (12 - 10)/ 10 × 100 = 2/10 × 100 = 20%.

Step 2; Koby measured his plant lower than his plant's original height. He measured it to be 85 cm while it was 100 cm tall. So Koby's measurement was off by 15cm. The percent error is calculated in the same way.

% error = (difference in values / actual value) × 100

Koby's % error = (100 - 85)/ 100 × 100 = 15/100 × 100 = 15%.

Step 3; Hugo had a percent error of 20% while Koby has a percent error of 15%. So Hugo had a higher percent error of the two.

fredd [130]3 years ago

3 0

Answer:

Step-by-step explanation:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

Show that if X is a geometric random variable with parameter p, then

Lubov Fominskaja [6]

Answer:

$\sum_{k=1}^{\infty} \frac{p(1-p)^{k-1}}{k}=-\frac{p ln p}{1-p}$

Step-by-step explanation:

The geometric distribution represents "the number of failures before you get a success in a series of Bernoulli trials. This discrete probability distribution is represented by the probability density function:"

$P(X=x)=(1-p)^{x-1} p$

Let X the random variable that measures the number os trials until the first success, we know that X follows this distribution:

$X\sim Geo (1-p)$

In order to find the expected value E(1/X) we need to find this sum:

$E(X)=\sum_{k=1}^{\infty} \frac{p(1-p)^{k-1}}{k}$

Lets consider the following series:

$\sum_{k=1}^{\infty} b^{k-1}$

And let's assume that this series is a power series with b a number between (0,1). If we apply integration of this series we have this:

$\int_{0}^b \sum_{k=1}^{\infty} r^{k-1}=\sum_{k=1}^{\infty} \int_{0}^b r^{k-1} dt=\sum_{k=1}^{\infty} \frac{b^k}{k}$ (a)

On the last step we assume that $0\leq r\leq b$ and $\sum_{k=1}^{\infty} r^{k-1}=\frac{1}{1-r}$ , then the integral on the left part of equation (a) would be 1. And we have:

$\int_{0}^b \frac{1}{1-r}dr=-ln(1-b)$

And for the next step we have:

$\sum_{k=1}^{\infty} \frac{b^{k-1}}{k}=\frac{1}{b}\sum_{k=1}^{\infty}\frac{b^k}{k}=-\frac{ln(1-b)}{b}$

And with this we have the requiered proof.

And since $b=1-p$ we have that:

$\sum_{k=1}^{\infty} \frac{p(1-p)^{k-1}}{k}=-\frac{p ln p}{1-p}$

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3 years ago

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olga2289 [7]

Answer:

there are no signs between the x and y and constant

it could be

2x+5y=15

2x+5y=-15

-2x+5y=15

2x-5y=15

for ax+by=c, the equation of a line paralell to that is

ax+by=d where a=a, b=b, and c and d are constants

(for this answer, I'm going to use 2x+5y=15)

given 2x+5y=15, the equation of a line paralell to that is 2x+5y=d

to find d, subsitute the point (4,-2), basically put 4 in for x and -2 for y to get the constant

2x+5y=d

2(4)+5(-2)=d

8-10=d

-2=d

the eqaution is 2x+5y=-2 (Only if the original equation is 2x+5y=-15

pls mark me brainlest

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2 years ago

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Answer:

x=1

Step-by-step explanation:

-16+x=-15

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After that you simplify.

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Answer:

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Step-by-step explanation:

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