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goblinko [34]
3 years ago
11

Find the surface area of a box measuring 4 inches long 3 inches wide and 6 inches tall

Mathematics
1 answer:
Rufina [12.5K]3 years ago
3 0

4*3

12

12*6

72

hope it help

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ind the length of the longest side of the rectangle whose vertices are given. A(2, 1), B(5, 4), C(0, 3), D(3, 6) 2 rad2 3 rad2 r
trasher [3.6K]

Distance between A and B  

= Distance between C and D  

= sqrt((4 - 1)^2 + (5 - 2)^2)  

= sqrt(3^2 + 3^2)  

= sqrt(2 * 3^2)  

= sqrt(3^2) * sqrt(2)  

= 3sqrt(2)  

Distance between B and C  

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= sqrt((4 - 3)^2 + (5 - 0)^2)  

= sqrt(1^2 + 5^2)  

= sqrt(26)  

Since sqrt(26) is more than 3sqrt(2), the length must be sqrt(26).

Hope this helps you.

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