Question

What is the slope of a line that is perpendicular to the line whose equation is 5y+2x=12?

Answer 1

Answer:

A

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange 5y + 2x = 12 into this form

Subtract 2x from both sides

5y = - 2x + 12 ( divide all terms by 5 )

y = - $\frac{2}{5}$ + $\frac{12}{5}$ ← in slope- intercept form

with slope m = - $\frac{2}{5}$

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{-\frac{2}{5} }$ = $\frac{5}{2}$ → A