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AysviL [449]
3 years ago
10

What is the slope of a line that is perpendicular to the line whose equation is 5y+2x=12?

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
8 0

Answer:

A

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange 5y + 2x = 12 into this form

Subtract 2x from both sides

5y = - 2x + 12 ( divide all terms by 5 )

y = - \frac{2}{5} + \frac{12}{5} ← in slope- intercept form

with slope m = - \frac{2}{5}

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{-\frac{2}{5} } = \frac{5}{2} → A

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