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3 years ago

What is the slope of a line that is perpendicular to the line whose equation is 5y+2x=12?

Mathematics

1 answer:

r-ruslan [8.4K]3 years ago

8 0

Answer:

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange 5y + 2x = 12 into this form

Subtract 2x from both sides

5y = - 2x + 12 ( divide all terms by 5 )

y = - $\frac{2}{5}$ + $\frac{12}{5}$ ← in slope- intercept form

with slope m = - $\frac{2}{5}$

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{-\frac{2}{5} }$ = $\frac{5}{2}$ → A

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1. Identify each situation in which a quantity grows or decays by a constant percent rate per unit interval. A. The number of ca

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Step-by-step explanation:

1) For each situation to grow or decay by a constant percent rate, it must be exponential. Therefore, the correct examples are

A. The number of cars sold doubles every year. It is a 200% growth every year.

D. Each time you start a car engine the remaining engine life decreases by 0.0075%. A case of decay

E. The number of people creating cat videos increases by 15% percent every year.

F. Computer technology increases by a factor of 3 every five years.

2) this is a case of exponential decay. The expression for exponential decay is

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Given that

r = 10% = 10/100 = 0.1

b = 50 kilograms

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3 years ago

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Answer:

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Step-by-step explanation:

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You are jumping off the 12 foot diving board at the municipal pool. You bounce up at 6 feet per second and drop to the water you

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Answer:

When do you hit the water?

1.075 seconds after you jump.

What is your maximum height?

the maximum height is 12.5626 ft

Step-by-step explanation:

The equation:

h(t) = -16*t^2 + 6*t + 12

Is the height as a function of time.

We know that the initial height is the height when t = 0s

h(0s) = 12

and we know that the diving board is 12 foot tall.

Then the zero in h(t)

h(t) = 0

Represents the surface of the water.

When do you hit the water?

Here we just need to find the value of t such that:

h(t) = 0 = -16*t^2 + 6*t + 12

Using the Bhaskara's formula, we get:

$t = \frac{-6 \pm \sqrt{6^2 - 4*(-16)*12} }{2*(-16)} = \frac{-6 \pm 28.4}{-32}$

Then we have two solutions, and we only care for the positive solution (because the negative time happens before the jump, so that solution can be discarded)

The positive solution is:

t = (-6 - 28.4)/-32 = 1.075

So you hit the water 1.075 seconds after you jump.

What is your maximum height?

The height equation is a quadratic equation with a negative leading coefficient, then the maximum of this parabola is at the vertex.

We know that the vertex of a general quadratic:

a*x^2 + b*x + c

is at

x = -b/2a

Then in the case of our equation:

h(t) = -16*t^2 + 6*t + 12

The vertex is at:

t = -6/(2*-16) = 6/32 = 0.1875

Evaluating the height equation in that time will give us the maximum height, which is:

h(0.1875) = -16*(0.1875 )^2 + 6*(0.1875) + 12 = 12.5626

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3 years ago

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Answer:

The given line segment whose end points are A(2,2) and B(3,8).

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if we have to find distance between two points (a,b) and (p,q) is

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AB= $\sqrt{(3-2)^2+(8-2)^2}=\sqrt{1+36}=\sqrt{37}$ = 6.08 (approx)

Line segment AB is dilated by a factor of 3.5 to get New line segment CD.

Coordinate of C = (3.5 ×2, 3.5×2)= (7,7)

Coordinate of D = (3.5×3, 3.5×8)=(10.5,28)

CD = AB × 3.5

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As the two lines are coincident , so their slopes are equal.

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