Total coins = 10 ( 4 + 3 + 3 = 10).
The probability of picking a nickel first = 4/10 = 2/5 ( 4 nickels out of 10 total).
The probability of picking a dime second = 3/9 = 1/3 ( 3 dimes out of 9 coins left).
The probability of picking the third coin as a quarter = 3/8 ( 3 quarters out of 8 coins left).
The probability of picking all three in that order = 2/5 x 1/3 x 3/8 = 1/20
Answer:
I think the answer is 22% but I am not sure
Step-by-step explanation:
Percentage solution with steps:
Step 1: We make the assumption that 50 is 100% since it is our output value.
Step 2: We next represent the value we seek with X
Step 3: From step 1, it follows that 100%=50
Step 4: In the same vein, x%=11.
Step 5: This gives us a pair of simple equations:
100%=50(1).
X%=11(2).
Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the left hand side of both equations have the same unit; we have
100% / X% = 11 / 50
X = 22%
Step 7: Taking the inverse (or reciprocal) of both sides yields
X% / 100% = 11 / 50
Therefore, 11 is 22% of 50.
The original price was 725.
Explanation:
"36% less than" means taking 36% away from 100%. 100-36 is 64, so 64% remains when 36% is taken away. So, 64% of the original table's price is 464.
So, if the original price was x, 464=0.64x
Solve this by dividing both sides by 0,64:
725=x
So, the original price was 725.
