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3 years ago

Pls hel fast a have to finish this quiz

Mathematics

2 answers:

SOVA2 [1]3 years ago

8 0

Answer:

So put the pi in the 3.14 box then 22/7 to where it says 3.142857143 or something (I can't really see the pic, but yeah that number) then you know the next answer :)

Step-by-step explanation:

Jet001 [13]3 years ago

8 0

Answer:

First is the pi sign, then 3.14, 22/7 in the last box

Step-by-step explanation:

CausE ♪~ ᕕ(ᐛ)ᕗ

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3x - 6 + 4 = -20

V125BC [204]

Answer:

I'm not sure what all that extra stuff is supposed to mean, but the answer to the top question is: x = -6

Step-by-step explanation:

3 0

3 years ago

Select the property of equality used to arrive at the conclusion. If x = 4, then 5x = 20 the addition property of equality the m

shtirl [24]

Answer:

The Division Property of Equality

Step-by-step explanation:

The Addition Property of Equality: When you add something to one side of the equation, you must add the same thing to the other side.

The Subtraction Property of Equality: When you subtract something from one side of the equation, you must subtract the same thing from the other side.

The Multiplication Property of Equality: When you multiply something to one side of the equation, you must multiply the same thing to the other side.

The Division Property of Equality: When you divide something from one side of the equation, you must divide the same thing from the other side.

In this case, you have to divide both sides of the equation by 5 to get x = 4. That means that the division property of equality was used.

I hope this helps! Have a great day!

8 0

3 years ago

Read 2 more answers

Please help me, I am not sure of the answer.

coldgirl [10]

I think it’s b not sure tho

6 0

3 years ago

Solve for y. -1 = 8+3y Simplify you answer as much as possible.

OleMash [197]

Answer:

-3

Step-by-step explanation:

$8+3y = -1\\3y = -9\\y = -3$

8 0

3 years ago

Read 2 more answers

Divide: (5 + 4i) / (-3 – 2i)

Phantasy [73]

Answer:

Step-by-step explanation:

$\frac{5+4i}{-3-2i}\\\\\mathrm{Apply\:complex\:arithmetic\:rule}:\\\\\quad \frac{a+bi}{c+di}\:=\:\frac{\left(c-di\right)\left(a+bi\right)}{\left(c-di\right)\left(c+di\right)}\:=\:\frac{\left(ac+bd\right)+\left(bc-ad\right)i}{c^2+d^2}\\\\a=5,\:b=4,\:c=-3,\:d=-2\\\\=\frac{\left(5\left(-3\right)+4\left(-2\right)\right)+\left(4\left(-3\right)-5\left(-2\right)\right)i}{\left(-3\right)^2+\left(-2\right)^2}\\\\Refine\\=\frac{-23-2i}{13}\\\\$

$\mathrm{Rewrite\:}\frac{-23-2i}{13}\mathrm{\:in\:standard\:complex\:form:\:}-\frac{23}{13}-\frac{2}{13}i\\$

8 0

3 years ago