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Naddika [18.5K]
2 years ago
11

WORTH 35 POINTS HELP MEEEEEEE PLEZ I NEED HELP

Mathematics
2 answers:
Alex Ar [27]2 years ago
7 0

Answer:

4x +y = 3

Step-by-step explanation:

Perpendicular lines have slopes that are the negative reciprocals of one another. When the equation of the line is written in standard form like this, the equation of the perpendicular line can be written by swapping the x- and y-coefficients and negating one of them. Doing this much would give you ...

 4x +y = (constant)

Note that we have chosen to make the equation read 4x+y, not -4x-y. The reason is that "standard form" requires the leading coefficient to be positive.

Now, you just need to make sure the constant is appropriate for the point you want the line to go through. So, it needs to be ...

 4(2) +(-5) = constant = 3

The line of interest has equation ...

 4x + y = 3

Paul [167]2 years ago
3 0

Answer:

y = x/4 - 22/4 (parallel line that passes through (2,-5)

Step-by-step explanation:

4y = x - 20\\y = x/4 - 5

here we isolated the original line

now we know that the line will have exactly the same slope but we need to find c in the new line: y = x/4 + c

so, we input the point (2,-5):

c  = - \frac{20}{4}  - \frac{2}{4}  = -\frac{22}{4} \\y = \frac{x}{4}  - \frac{22}{4}

check that it works: y = 2/4 - 22/4 = -20/4 = -5

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4 0
3 years ago
Y-2 = -3(x + 6), write the equation of the line in slope intercept form.
lisov135 [29]

Answer:

y = -3x - 16

Step-by-step explanation:

Point-slope form: y - y1 = m(x - x1)

Given: y - 2 = -3(x + 6)

Slope-intercept form: y = mx + b

To write the equation in slope-intercept form, we need to know the slope(m) and the y-intercept(b). By looking at the given equation, we can see that the slope is -3. We are also given the value of one point: (-6, 2).

To find the y-intercept, input the given values of the slope and the point into the equation format and solve for b:

y = mx + b

2 = -3(-6) + b

2 = 18 + b

Subtract 18 from both sides of the equation to isolate b:

2 - 18 = 18 - 18 + b

-16 = b

The y-intercept is -16.

Now that we know the slope and the y-intercept, we can write the equation:

y = -3x - 16

8 0
3 years ago
Im a little stuck on this​ (please show how you did it)
nikklg [1K]

Answer:

all work is shown / pictured

5 0
3 years ago
Segment PE has endpoints P(-4,4) and E(0,-4). Find the coordinates of point Q such that PQ:QE is 1:3. Enter the coordinates belo
Natalka [10]

Answer:

(-3, 2)

Step-by-step explanation:

Given that point Q, partitions segment PE, such that PQ:QE is 1:3, coordinates of point Q is found using the formula below:

x = \frac{mx_2 + nx_1}{m + n}

y = \frac{my_2 + ny_1}{m + n}

Where,

P(-4, 4) = (x_1, y_1)

E(0, -4) = (x_2, y_2)

m = 1, n = 3

Plug in the necessary values to find x and y coordinates for point Q as follows:

x = \frac{mx_2 + nx_1}{m + n}

x = \frac{1(0) + 3(-4)}{1 + 3}

x = \frac{0 - 12}{4}

x = \frac{-12}{4}

x = -3

y = \frac{my_2 + ny_1}{m + n}

y = \frac{1(-4) + 3(4)}{1 + 3}

y = \frac{-4 + 12}{4}

y = \frac{8}{4}

y = 2

The coordinates of the point Q are (-3, 2))

8 0
3 years ago
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