All categories

3 years ago

Question 6 Find the area of the rhombus below. 5 ft ーー 8 ft A= feet squared

Mathematics

1 answer:

Viefleur [7K]3 years ago

5 0

There are two samples of liquid water in two different containers.
The temperature of water in both containers is 70 degrees
Celsius. However, there are 100 grams of water in container A There are two samples of liquid water in two different containers.
The temperature of water in both containers is 70 degrees
Celsius. However, there are 100 grams of water in container A There are two samples of liquid water in two different containers.
The temperature of water in both containers is 70 degrees
Celsius. However, there are 100 grams of water in container A
2881818118 82$&1$2$1&1&1 iejqkqjqbsbwhbw 82&1&1&1&2!/ jakwjqhqjqk

You might be interested in

−6(4a +3) Multiply the polynomial below

olchik [2.2K]

Answer:

$- 6(4a + 3) \\ =( - 6 \times 4a) + ( - 6 \times 3) \\ = - 24a - 18 \\$

5 0

3 years ago

Read 2 more answers

Mark spent $21 on a magazine and some candy bars. If the magazine cost $5 and each candy bar cost $2, then how many candy bars d

Lana71 [14]

Answer:8 candy bars because 21-5=16/2=8 candy bars.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Which expression is equivalent to

pychu [463]

Answer:

Step-by-step explanation:

i cannot find an answer from the expression but i can guess if you didnt follow pemdas, it would be d

3.5 × 102 is 357

(8 × 10−4) + (6 × 10−4) is 132

132/357= .369 or .37 or 0 simplified

d is 4*10-10

10-10 is 0

4*0 is 0

8 0

3 years ago

Solve differential equation. Just explain the first 2 steps

lutik1710 [3]

(1) will write us of the following form

$\dfrac{dy}{dx}+y^2\sin x=0\\ \\
$

(2) [do not it need explanation]

$\dfrac{dy}{dx}=-y^2\sin x\\ \\
$

(3) Left place variable "y" and right place, variable "x" like this

$\dfrac{dy}{y^2}=-\sin x\, dx\\ \\$

(4) Integrate both members

$\displaystyle
\int \dfrac{dy}{y^2}=\int-\sin x\, dx\\ \\$

(5) Solve us the integrals

$-\dfrac{1}{y}= \cos x+C$

(6) Isolate variable "y"

$\boxed{y=-\dfrac{1}{\cos x+C}}$

C: any cosntant

4 0

2 years ago

A 24-centimeter by 119-centimeter piece of cardboard is used to make an open-top box by removing a square from each corner of th

satela [25.4K]

Answer:

The size square removed from each corner = 32.15 cm²

Step-by-step explanation:

The volume of the box = Length * Breadth * Height

Let r be the size removed from each corner

Note that at maximum volume, $\frac{dV}{dr} = 0$

The original length of the cardboard is 119 cm, if you remove a size of r (This typically will be the height of the box) from the corner, since there are two corners corresponding to the length of the box, the length of the box will be:

Length, L = 119 - 2r

Similarly for the breadth, B = 24 - 2r

And the height as stated earlier, H = r

Volume, V = L*B*H

V = (119-2r)(24-2r)r

V = r(2856 - 238r - 48r + 4r²)

V = 4r³ - 286r² + 2856r

At maximum volume dV/dr = 0

dV/dr = 12r² - 572r + 2856

12r² - 572r + 2856 = 0

By solving the quadratic equation above for the value of r:

r = 5.67 or 42

r cannot be 42 because the size removed from the corner of the cardboard cannot be more than the width of the cardboard.

Note that the area of a square is r²

Therefore, the size square removed from each corner = 5.67² = 32.15 cm²

5 0

3 years ago