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3 years ago

Marques drops a plate from a height of 5 feet. When will the plate hit the ground?

Mathematics

1 answer:

nadya68 [22]3 years ago

4 0

Answer:

<u>Option A. about 1 seconds</u>

Step-by-step explanation:

Let the initial speed u and the final speed v

Time t , distance s and acceleration of gravity g

The equation of motion are:

v = u + gt ⇒(1)

s = ut + 0.5 gt² ⇒(2)

v² = u² + 2gs ⇒(3)

Marques drops a plate from a height of 5 feet.

So, u = 0 , s = 5 ft , g = 9.8 m/sec²

Substitute at (2)

s = ut + 0.5 gt²

5 = 0 * t + 0.5 * 10 * t²

∴ t² = 5/(0.5*9.8) = 1.02

∴ t = √1.02 = 1.01 seconds ≈ 1 seconds (to the nearest integer)

<u>The answer is option A. about 1 seconds</u>

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The table represents the function f (x) = 3x – 1.

Kruka [31]

Answer:2.0/5 68 The 1st table represents a function

Step-by-step explanation:

* Lets explain how to solve the problem

- Function is a relation where each input has a single output

- The notation of the function is f(x) = y , where x is the input of the

function and y is the out put of the function

- The domain of the function is x and the range of the function is y

* Lets find which table represent a function

# First table:

x y

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- In the first table

∵ -3 has only -1

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∵ -2 has only -1

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∵ Every x has a single y

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∴ The 1st table represents a function

- In the second table

x y

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∵ x = -5 has y = -5 and y = 5

∴ One x has two values of y

∴ The table doesn't represent a function

- In the third table

x y

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∴ One x has two values of y

∴ The table doesn't represent a function

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x y

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3 years ago

Read 2 more answers

give the standard form, degree, leading coefficient and the constant term of the function h(x) = (2x+1)² (2x-3)

Softa [21]

Answer:

The standard form is: $h(x) = 8x^3 - 4x^2 - 10x - 3$

The function is of the 3rd degree.

The leading coefficient is 8.

The constant term is -3.

Step-by-step explanation:

Placing in standard form:

To place in standard form, we solve the operations. So

$h(x) = (2x+1)^2(2x-3)$

$h(x) = (4x^2 + 4x + 1)(2x - 3)$

$h(x) = 8x^3 - 12x^2 + 8x^2 - 12x + 2x - 3$

$h(x) = 8x^3 - 4x^2 - 10x - 3$

Degree:

The degree is given by the highest power of x, which, in this exercise, is 3.

Leading coefficient:

The leading coefficient is the term that multiplies the highest power of x. In this exercise, the higher power of x is $x^3$ , which is multiplied by 8. So the leading coefficient is 8.

Constant term:

The constant term is the one which does not multiply a power of x. So in this exercise, it is -3.

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ANSWER AT THE BOTTOM BELOW

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$(9)^{2x}(27)^{1-x}=(81)^{2x+1}$

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Answer:

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The setup looks like

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