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Rina8888 [55]
3 years ago
14

-16 = 4/3x -8 Solve please

Mathematics
1 answer:
lbvjy [14]3 years ago
4 0
-16=4/3x-8
add 8 to both sides
-8=4/3x
multiply both sides by 3
-24=4x
divide both sides by 4
-6=x
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Which of the following equations is of the parabola whose vertex is at (2, 3), axis of symmetry parallel to the y-axis and p = 4
lora16 [44]

Answer:

option A.) y-3 = 1/16 (x-2)^2

Step-by-step explanation:

we know that

If the axis of symmetry is parallel to the y-axis, then we have a vertical parabola

The equation of a vertical parabola is equal to

4p(y-k)=(x-h)^{2}

where

(h,k) is the vertex

In this problem we have

(h,k)=(2,3)

p=4

substitute

4(4)(y-3)=4(4)(x-2)^{2}

16(y-3)=(x-2)^{2}

(y-3)=(1/16)(x-2)^{2}

8 0
3 years ago
What is the average rate of change of the function f(x)=2(3)x from x = 2 to x = 4?
Dvinal [7]
this is kinda easy and im gonna assume that the 4 is a exponent cuz f(2)=2(3)^4 then f=81
4 0
4 years ago
What's the answer and plz answer honestly??
kolezko [41]
5,000,000,000

300,000
8 0
3 years ago
Kelly deposits $3,000 at a rate of 5.2% compounded quarterly. With no additional deposits or withdrawals, what is the account ba
lorasvet [3.4K]
\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$3000\\
r=rate\to 5.2\%\to \frac{5.2}{100}\to &0.052\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four}
\end{array}\to &4\\
t=years\to &10
\end{cases}
\\\\\\
A=3000\left(1+\frac{0.052}{4}\right)^{4\cdot 10}\implies A=3000(1.013)^{40}
\\\\\\
A\approx 5029.201878874637
7 0
3 years ago
Read 2 more answers
Can someone help me with this question?
belka [17]
Option 3 (1/4 x 60) since 59 is close to 60 and 25% can be rewritten as 1/4
4 0
3 years ago
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