From the question we can deduce the formula to be 16 + 3n = 76
3n - 76 - 16
3n = 60
n = 20
20 is the answer.
Answer: 101000
Step-by-step explanation: It would be rounded to 101000 because the nearest 100 would be a 1000.
Answer:

Step-by-step explanation:
The fractional exponent m/n is often translated to radical form as ...
![x^{\frac{m}{n}}=\sqrt[n]{x^m}](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%3D%5Csqrt%5Bn%5D%7Bx%5Em%7D)
In this case, I find it easier to evaluate as ...
![x^{\frac{m}{n}}=(\sqrt[n]{x})^m=\boxed{(\sqrt{9})^3=3^3=27}](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%3D%28%5Csqrt%5Bn%5D%7Bx%7D%29%5Em%3D%5Cboxed%7B%28%5Csqrt%7B9%7D%29%5E3%3D3%5E3%3D27%7D)
Answer:
Use multitape Turing machine to simulate doubly infinite one
Explanation:
It is obvious that Turing machine with doubly infinite tape can simulate ordinary TM. For the other direction, note that 2-tape Turing machine is essentially itself a Turing machine with doubly (double) infinite tape. When it reaches the left-hand side end of first tape, it switches to the second one, and vice versa.