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Anastaziya [24]
3 years ago
5

Please help!! asap!!!

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
6 0

Solution:

Rewrite 3 ≥ y - 2 for easier calculation:

y - 2 ≤ 3

Move the term:

y ≤ 3 + 2

y ≤ 5

When graphing the solution, filled dot (black arrow) is used for ≤ and ≥ while empty dot (white arrow) is used for < >

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I think it is 11 Feet

Step-by-step explanation:

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3 years ago
20. Based on student records, 25% of the students at a large high school have a
Elenna [48]

Answer:

(E) 0.71

Step-by-step explanation:

Let's call A the event that a student has GPA of 3.5 or better, A' the event that a student has GPA lower than 3.5, B the event that a student is enrolled in at least one AP class and B' the event that a student is not taking any AP class.

So, the  probability that the student has a GPA lower than 3.5 and is not taking any AP  classes is calculated as:

P(A'∩B') = 1 - P(A∪B)

it means that the students that have a GPA lower than 3.5 and are not taking any AP  classes are the complement of the students that have a GPA of 3.5 of better or are enrolled in at least one AP class.

Therefore, P(A∪B) is equal to:

P(A∪B) = P(A) + P(B) - P(A∩B)

Where the probability P(A) that a student has GPA of 3.5 or better is 0.25, the probability P(B) that a student is enrolled in at least one AP class is 0.16 and the probability P(A∩B) that a student has a GPA of 3.5 or better and is enrolled  in at least one AP class is 0.12

So, P(A∪B) is equal to:

P(A∪B) = P(A) + P(B) - P(A∩B)

P(A∪B) = 0.25 + 0.16 - 0.12

P(A∪B) = 0.29

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P(A'∩B') = 1 - P(A∪B)

P(A'∩B') = 1 - 0.29

P(A'∩B') = 0.71

5 0
3 years ago
Read 2 more answers
Can someone help with this please
nasty-shy [4]

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To add and subtract polynomials, combine only like terms. When doing it vertically, stack polynomials and line up the same bases and exponents. Once this is done, simply add and subtract the coefficients.

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+ 12x^2 -22xy + 8x

_________________

22x^2 -10xy + 12x

Here we added 10 + 12 = 22, 12 + -22 = -10 and 4 + 8 = 12.

6 0
3 years ago
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The tickets aren't replaced, so multiply the probabilities, decreasing the  denominator each time.

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Nominal.

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