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Arturiano [62]
4 years ago
11

13 point question, Surds, geometry and Algebra. Help me please ! :( < 3

Mathematics
1 answer:
KIM [24]4 years ago
6 0

Answer:

A)  Tan 60° \sqrt{3} = 1.732

B)  H = 12 unit

C)  Area of triangle = 41.569 unit²

Step-by-step explanation:

As shown in figure, the triangle with cone angle of 60° and base value 4\sqrt{3} unit

A) Now, Tan 60° = \sqrt{3}

   Or, Tan 60° = 1.732

B) To  find value of h

   since TanФ = \frac{Perpendicular}{Base}

   So,     Tan 60° = \frac{h}{4\sqrt{3} }  

             \sqrt{3} = \frac{h}{4\sqrt{3} }

           ∴(\sqrt{3}) × (4\sqrt{3} = h

           ∴ h = 12 unit

C) Area of this triangle = \frac{1}{2} × Perpendicular × Base

                                     = \frac{1}{2} × h ×4\sqrt{3}

      ∵ Perpendicular  h = 12 unit

   So, Area = \frac{1}{2} × 12 × 4\sqrt{3}

   Hence Area of triangle = 41.569 unit²

ANSWER

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We could start by finding the lowest common multiple of 2, 3, 4, 5, and 6, which is 60. Then, we can consider the next few multiples: 120, 180, 240, 300...

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Hope this all makes sense.
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If t follows a t7 distribution, find t0 such that (a) p(|t | &lt; t0) = .9 and (b) p(t &gt; t0) = .05.
Thepotemich [5.8K]

Answer:

a) P(-t_o < t_7

Using the symmetrical property we can write this like this:

1-2P(t_7

We can solve for the probability like this:

2P(t_7

P(t_7

And we can find the value using the following excel code: "=T.INV(0.05,7)"

So on this case the answer would be t_o =\pm 1.895

b) For this case we can use the complement rule and we got:

1-P(t_7

We can solve for the probability and we got:

P(t_7

And we can use the following excel code to find the value"=T.INV(0.95;7)"

And the answer would be t_o = 1.895

Step-by-step explanation:

Previous concepts

The t distribution (Student’s t-distribution) is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".

The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.  

The degrees of freedom represent "the number of independent observations in a set of data. For example if we estimate a mean score from a single sample, the number of independent observations would be equal to the sample size minus one."

Solution to the problem

For this case we know that t \sim t(df=7)

And we want to find:

Part a

P(|t|

We can rewrite the expression using properties for the absolute value like this:

P(-t_o < t_7

Using the symmetrical property we can write this like this:

1-2P(t_7

We can solve for the probability like this:

2P(t_7

P(t_7

And we can find the value using the following excel code: "=T.INV(0.05,7)"

So on this case the answer would be t_o =\pm 1.895

Part b

P(t>t_o) =0.05

For this case we can use the complement rule and we got:

1-P(t_7

We can solve for the probability and we got:

P(t_7

And we can use the following excel code to find the value"=T.INV(0.95;7)"

And the answer would be t_o = 1.895

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