We could start by finding the lowest common multiple of 2, 3, 4, 5, and 6, which is 60. Then, we can consider the next few multiples: 120, 180, 240, 300...
However, because we need a remainder of 1 when our number is divided by each of these numbers (2,3,4,5,6), we want to go one above each of these multiples. So we're talking about 61, 121, 181, 241, 301... Those are the numbers that will satisfy the "remainder of 1" part of the question.
Now, we need to find out which one satisfies the other part of the question, which just requires dividing each of these numbers by 7 to see which is divisible by 7 (in other words, which one gives us a remainder of zero when we divide by 7).
301 does it. 301/7 = 43. So 301 is a multiple of 7 and therefore will yield no remainder when divided by 7.
First, let's convert the givens to decimals to make calculations easier: 2 (3/4) = 2.75 9(5/8) = 9.625
We are given that: Josie can hike 2.75 miles in one hour. To know the time that Josie would take to hike 9.625 miles, we will simply do cross multiplication as follows: 2.75 miles ..........> 1 hour 9.625 miles .............> ?? hours
I think it would be A, because if she jogged the same amount each day she jogged then all you need to do is multiply how much she jogged by how many days she jogged.
