What number divided by 2 3 4 5 6 has a remainder of 1 but when divided by 7 has no remainder?

1 answer:

3 0

301

We could start by finding the lowest common multiple of 2, 3, 4, 5, and 6, which is 60. Then, we can consider the next few multiples: 120, 180, 240, 300...

However, because we need a remainder of 1 when our number is divided by each of these numbers (2,3,4,5,6), we want to go one above each of these multiples. So we're talking about 61, 121, 181, 241, 301... Those are the numbers that will satisfy the "remainder of 1" part of the question.

Now, we need to find out which one satisfies the other part of the question, which just requires dividing each of these numbers by 7 to see which is divisible by 7 (in other words, which one gives us a remainder of zero when we divide by 7).

301 does it. 301/7 = 43. So 301 is a multiple of 7 and therefore will yield no remainder when divided by 7.

Hope this all makes sense.

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A. Five places to the left

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Before putting a number into scientific notation, you need to know which number is a significant figures. In this question, there are two significant figure which is 39, all zeroes on the right is insignificant. We can move the decimal to convert the number into 3.9 * 10^5. Basically you need to move the decimal to the left if the exponent positive, but move it to the right if its negative. The exponent is +5 so we move the decimal points 5 places to the left.

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{13.7756,18.2244}

Step-by-step explanation:

Given the sample size, the margin of error can be calculated with the formula $M=Z*\frac{\sigma}{\sqrt{n}}$ where Z is the critical value for the desired confidence level, σ is the population standard deviation, and n is the sample size. Therefore, our margin of error for a 90% confidence level is:

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The formula for a confidence interval is $CI=\bar{x}+M$ where x-bar is the sample mean. Therefore, the 90% confidence interval for the mean amount of sushi pieces a person can eat is: