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lubasha [3.4K]
3 years ago
10

Select all of the coefficients in the expression. 12xy3 + 2x5y + 4x5y2 + 7x5y.

Mathematics
2 answers:
DedPeter [7]3 years ago
5 0

Answer:

The coefficients are simply 12, 2, 4, and 7.

Step-by-step explanation:

Coefficients are the numbers that come before terms. Each term has a coefficient before it.

Sauron [17]3 years ago
5 0

Answer:

The coefficients in the expression are: 12, 2,4 and 7

Step-by-step explanation:

Expressions like this 12xy^{3} +2x^{5}y+4x^{5}x^{2}+7x^{5}y are known as polynomials in two variables.

In a general form a polynomial in two variables is an expression that can be written in the form:

P(x,y) = a_{0,0}+a_{1,0}x+a_{0,1}y+a_{2,0}x^{2}+a_{1,1}xy+a_{0,2}y^{2}+...+a_{n,0}x^{n}+...+a_{0,n}y^{n}, where a_{0,0} or a_{n,0} are called the coefficients.

To get polynomial coefficients, you can take the numbers in front of each terms, for example 12xy^{3} is known as term and the coefficient is 12.

Or compare the general form of a polynomial with the polynomial 12xy^{3} +2x^{5}y+4x^{5}x^{2}+7x^{5}y and you find that the coefficients in the expression are: 12, 2,4 and 7

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The equation of a line passing through point (4, -1) and perpendicular to the line whose equation is 2x - y - 7 = 0 is y = -1/2x + 1

<h3>Equation of a line</h3>

A line is the shortest distance between two points. The equation of a line in point-slope form and perpendicular to a line is given as;

y - y1 = -1/m(x-x1)

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Given the following

Point = (4, -1)

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Learn more on equation of a line here: brainly.com/question/13763238

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