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Dimas [21]
3 years ago
14

The cylindrical water tank on a semitrailer has a length of 20 feet. The volume of the tank is equal to the product of pi, the s

quare of the radius of the tank, and the length of the tank. Let V represent the volume of the tank, r represent the radius of the tank, h represent the length of the tank.
Create an equation could be used to find volume, V, of the cylindrical tank.

Mathematics
1 answer:
Bogdan [553]3 years ago
7 0

Answer:

V = 20πr²

Step-by-step explanation:

In this question, volume of the cylindrical tank has been defined as,

Volume V of the tank = Product of π, the square of the radius of the tank 'r' and the length of the tank 'h'.

Therefore, formula to calculate the formula will be,

V = πr²h

If the length of the cylindrical trailer is,

h = 20 feet

Then the volume of the trailer will be,

V = πr²(20)

V = 20πr²

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Find the coordinates for the midpoint of the segment with endpoints given 12,4 and -8,8
borishaifa [10]
<h2>Hello!</h2>

The answer is:

The coordinates of the midpoint are:

x-coordinate=2\\y-coordinate=6

<h2>Why?</h2>

We can find the midpoint of the segment with the given endpoints using the following formula.

The midpoint of a segment is given by:

MidPoint=(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})

We are given the points:

(12,4)\\

and

(-8,8)\\

Where,

x_{1}=12\\y_{1}=4\\x_{2}=-8\\y_{2}=8

So, calculating the midpoint, we have:

MidPoint=(\frac{12+(-8)}{2},\frac{4+8}{2})

MidPoint=(\frac{4}{2},\frac{12}{2})

MidPoint=(2,6)

Hence, we have that the coordinates of the midpoint are:

x-coordinate=2\\y-coordinate=6

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8 0
3 years ago
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A wooden toy kit has different painted solids. One solid is a cylinder with diameter 2cm and height 2cm. what is it's volume
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2 years ago
WILL GIVE BRAINLIEST!!! Given tan(theta) = 4/3 and pi &lt; theta &lt; (3pi)/2, find cos(2theta).
babymother [125]

Answer:  \cos 2 \theta = \dfrac{-7}{25}

Step-by-step explanation:

Given: \tan \theta = \dfrac{4}{3}  and  \pi < \theta< \dfrac{3\pi }{2}

To find: \cos 2 \theta

Now as we know

\cos 2x = \dfrac{1- \tan ^2 x}{1+ \tan ^2 x}

So we have

\cos 2 \theta = \dfrac{1-(\dfrac{4}{3} )^2}{1+(\dfrac{4}{3} )^2} \\\\\Rightarrow \cos 2 \theta = \dfrac{1- \dfrac{16}{9} }{1+ \dfrac{16}{9} } = \dfrac{\dfrac{9-16}{9} }{\dfrac{9+16}{9}} = \dfrac{-7}{25}

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3 years ago
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