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notsponge [240]
3 years ago
10

Blue, brown, and green beetles from a forest migrated to a rocky mountain after a natural disaster. In the new environment, brow

n beetles can camouflage themselves from predators better than the green beetles and blue beetles can. Which outcome is most likely for the future population of beetles?
Most beetles will be blue and green because predators rely on them for food.



Most of the beetles will be brown because they have a higher likelihood of reaching reproductive age.



The distribution of the three colors will be equal to preserve genetic variance in the population.



The bodies of the offspring will have all three colors because body color is an incomplete dominance inheritance pattern.
Biology
2 answers:
Natasha2012 [34]3 years ago
4 0

Answer: Most of the beetles will be brown because they have a higher likelihood of reaching reproductive age.

Natural selection is the process of selection by nature in which an individual organism exhibiting more favorable phenotypic characteristics has more chances of survival and reproduction in it's corresponding environment.

In the new environment, brown beetles can camouflage themselves from predators better than the green beetles and blue beetles can. This is because of the fact that brown color of beetle is a better phenotypic trait which favors the survival of brown beetles over green and blue color. Therefore, the survived brown beetles will reproduce and grow in number.    

Aliun [14]3 years ago
3 0
The second one I guess,because if only the brown beetles can protect themselves from predators than later on the blue and green beetles might go extinct and only the brown ones will survive.........I think so..
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Explanation:

Answering this question requires two steps.

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- The couple has already had one affected child.

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Let ( M = normal gene ) and ( m = mutated gene ). Since the condition is recessive, the affected child can be assumed to have a “mm” genotype. Barring the possibility of a de novo mutation (which are assumed to be rare), the affected child must have inherited one ”m” allele from each parent. Since both of them are unaffected, however, we can assume that they are both carriers (genotype “Mm”). In conclusion, 1/4 of their offspring (25%) <em>for any given pregnancy</em> may be expected to have albinism. See the resulting Punnett square:

<u>       |      M    |      m   </u>

<u>M    |    MM   |    Mm  </u>

<u>m    |    Mm   |    mm  </u>

Note that the question asks about the probability that not one but two consecutive births result in affected children. Since it can be assumed that both events are independent (meaning: the outcome of a pregnancy does not influence the outcome of following ones), we may apply the rule of multiplication for probabilities. The final answer is therefore 1/4 * 1/4 = 1/16.

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