4 years ago

How many solutions does the system of equations have Y = 4x+3 and 2Y-8x = 3

Mathematics

1 answer:

just olya [345]4 years ago

7 0

Answer:

The system has no solution.

Step-by-step explanation:

Write the system as

y - 4x =3

2y - 8x = 3

The 2nd equation can be written as

2(y - 4x)

and the system would be

y - 4x =3

2(y - 4x) = 3

Now, call y -4x = z. Then we would have the system

z = 3

2z = 3

But if z =3 then 2z = 6 and we have a contradiction.

We conclude that the system has no solution.

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