How many solutions does the system of equations have Y = 4x+3 and 2Y-8x = 3
1 answer:
Answer:
The system has no solution.
Step-by-step explanation:
Write the system as
y - 4x =3
2y - 8x = 3
The 2nd equation can be written as
2(y - 4x)
and the system would be
y - 4x =3
2(y - 4x) = 3
Now, call y -4x = z. Then we would have the system
z = 3
2z = 3
But if z =3 then 2z = 6 and we have a contradiction.
We conclude that the system has no solution.
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本题已由中国数学会官方解答(现有会员:3人)