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sertanlavr [38]
3 years ago
11

How many solutions does the system of equations have Y = 4x+3 and 2Y-8x = 3

Mathematics
1 answer:
just olya [345]3 years ago
7 0

Answer:

The system has no solution.

Step-by-step explanation:

Write the system as

y - 4x =3

2y - 8x = 3

The 2nd equation can be written as

2(y - 4x)

and the system would be

y - 4x =3

2(y - 4x) = 3

Now, call y -4x = z. Then we would have the system

z = 3

2z = 3

But if z =3 then 2z = 6 and we have a contradiction.

We conclude that the system has no solution.

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I am pretty sure the answer is 82.5 unrounded.
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Ne4ueva [31]

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17+a

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What’s the equation to this table?Pls help.Use y=mx+b
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Step-by-step explanation

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6 0
2 years ago
The quantity demanded x of a certain brand of DVD player is 3000/week when the unit price p is $485. For each decrease in unit p
ANTONII [103]

Answer:

Demand Equation: q = 15125 - 25p.

Supply Equation: 80p - 24000 = 9q.

Equilibrium Price: $525.

Equilibrium Quantity: 2000 units.

Step-by-step explanation:

To solve this question, first, the demand equation has to be calculated. Let price be on the y-axis and quantity by on the x-axis. It is given that p = $485 when q = 3000 units. This can also be written as (q₁, p₁) = (3000, 485). It is also given that when the price goes down by $20, the quantity increases by 500 units. Therefore, (q₂, p₂) = (3500, 465). Due to the statement "For each decrease in unit price of $20 below $485, the quantity demanded increases by 500 units", the demand function will be linear i.e. a straight line. This is because the word "for each" has been used. Therefore, finding the equation of the demand function:

(p - p₁)/(q - q₁) = (q₂ - q₁)/(p₂ - p₁).

(p - 485)/(q - 3000) = (465 - 485)/(3500 - 3000).

(p - 485)/(q - 3000) = (-20)/(500).

(p - 485)/(q - 3000) = -1/25.

25*(p - 485) = -1*(q - 3000).

25p - 12125 = -q + 3000.

25p + q = 15125.

q = 15125 - 25p. (Demand Equation).

Second, find the supply equation. It is given that the suppliers will not sell the product below or at the price of $300. Therefore, (q₁, p₁) = (0, 300). Also, the suppliers will sell 2000 units if the price is $525. Therefore, (q₂, p₂) = (2000, 525). Since it is mentioned that supply equation is linear, therefore:

(p - p₁)/(q - q₁) = (q₂ - q₁)/(p₂ - p₁).

(p - 300)/(q - 0) = (525 - 300)/(2000 - 0).

(p - 300)/(q) = (225)/(2000).

(p - 300)/(q) = 9/80.

80*(p - 300) = 9*(q).

80p - 24000 = 9q. (Supply Equation).

Equilibrium exists when demand = supply. This means that the demand and the supply equations have to be solved simultaneously. Therefore, put demand equation in supply equation:

80p - 24000 = 9(15125 - 25p).

80p - 24000 = 136125 - 225p.

305p = 160125.

p = $525.

Put p = $525 in demand equation:

q = 15125 - 25p.

q = 15125 - 25(525).

q = 15125 - 13125.

q = 2000 units.

To summarize:

Demand Equation: q = 15125 - 25p!!!

Supply Equation: 80p - 24000 = 9q!!!

Equilibrium Price: $525!!!

Equilibrium Quantity: 2000 units!!!

8 0
3 years ago
3. A warehouse holds 7,140 shoeboxes. Each aisle holds the same number of
s2008m [1.1K]

Answer:

1) b, c, d

2) d

3) a, c, d

Step-by-step explanation:

Just find the number that can divide by the whole. Say the question was

A pet shop have 20 pets. The same amount of pets are in each room. How many rroms could there be?

If there were 4 rooms, 5 pets would be in each. 20÷4=5. 4 goes into 20 so 4 could be an answer.

If there were 3 rooms, 6 rooms would have 3 pets and 2 would be left over. So it wouldn't work. You just need to find the number that goes into the whole with no remainder.

4 0
3 years ago
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