Answer:
(x² + 7x + 6) ÷ (x² + 2x + 1)
This should be in the form of a fraction, I just don't know how to format it that way on here.
Step-by-step explanation:
Since your denominators are equal on both fractions, you just need to subtract your numerators.
3x² + 9x + 12 - (2x² + 2x + 6)
When there is a - in front of an expression in parenthesis, you should change the sign of each term in the expression of the numerator being subtracted.
So this:
2x² + 2x + 6
Will become this:
2x² - 2x - 6
This is how it will look:
3x² + 9x + 12 - 2x² - 2x - 6
Now all you have to do is collect the like terms.
3x² and -2x² are like terms so you will add them together: 3x² + (-2x²) = 3x² - 2x² = x²
This is how your numerator should look so far:
x² + 9x + 12 - 2x - 6
Now we move on to the next like terms.
9x and -2x are like terms so we add them together: 9x + (-2x) = 9x - 2x = 7x
This is how your numerator should look so far:
x² + 7x + 12 - 6
Now we move on to the last set of like terms.
12 and -6 are like terms so we add them together: 12 + (-6) = 12 - 6 = 6
This is how your numerator should be now:
x² + 7x + 6
Now all you have to do is put your numerator on top of your denominator which is the same as in the start of your equation (x² + 2x + 1).
You are done! I hope this was clear and you understand :)
