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Artemon [7]
3 years ago
10

What is the Answer I need the real answer I’m stuck on it

Mathematics
1 answer:
lara31 [8.8K]3 years ago
5 0

Answer:

multiply both sides by 3x + 7

Step-by-step explanation:

this will eliminate the fraction in the equation and therefore make it easier to isolate x

hope this helps :)

You might be interested in
c) If an initial investment of $ 35,000 grows to $257,000 in 15 years, what annual interest rate, continuously compounded, was e
castortr0y [4]

Answer: 13.29%

Step-by-step explanation:

The formula to calculate the compound amount (compounded continuously) is given by :-

A=Pe^{rt}, where P is the principal amount , r is the rate of interest ( in decimal) and t is the time period.

Given : P= $ 35,000 , A=  $257,000 and t=15 years

To find : r , we substitute all the values in the above formula , we get

257000=(35000)e^{15r}\\\\\Rightarrow\ e^{15r}=\dfrac{257000}{35000}\\\\\Rightarrow\ e^{15r}=7.3428

Taking natural log on both the sides , we get

15r=\ln(7.3428)\\\\\Rightarrow\ 15r=1.9937\\\\\Rightarrow\ r=\dfrac{1.9937}{15}0.132913333333\approx0.1329=13.29\%

Hence, the annual interest rate = 13.29%

6 0
3 years ago
Math problem 10 points!
zubka84 [21]
The answer is A that’s the answer
4 0
3 years ago
What is the value of \dfrac{x^2}{y^4}
Nimfa-mama [501]

Answer:

4

Step-by-step explanation:

x^2/ y^4

Let x=8 and y=2

8^2 / 2^4

PEMDAS says powers first

64 / 16

Divide next

4

3 0
3 years ago
Read 2 more answers
Taylor bought 6 tickets to a movie. The price of each ticket was the same. After he bought the tickets, his account balance show
Sladkaya [172]

It is -11.34

-$68.04 divide by 6 is -$11.34, so instead of 11.34, it's -11.34

3 0
3 years ago
Four children have small toys. The first child has 1/10 of the toys, the second child has 12 more toys than the first, the third
GREYUIT [131]
Let the total toys be x.

The first has (1/10)x =  x/10


The third child has one more toys than the first =  x/10  + 1

The fourth has double of the third:  =  2* (x/10 + 1)  =  2x/10 + 2


Since we know that the second child has 12 more toys than the first

Therefore the Second  minus First = 12.


First let us find the second.

1st + 2nd + 3rd + 4th = x

x/10   +  2nd +  (x/10 + 1) + (2x/10 + 2) = x

2nd + x/10  + x/10 + 1 + 2x/10 + 2 = x

2nd + x/10 + x/10 + 2x/10 + 1 + 2  = x

2nd + 4x/10 + 3 = x

2nd = x - 4x/10 - 3

2nd =  6x/10  - 3

But recall

2nd - 1st = 12

6x/10 - 3 - x/10 = 12

6x/10 - x/10 = 12 + 3

5x/10 = 15

5x =  15 * 10

x  = 15*10 /5

x = 30

So there were 30 toys in all.
3 0
3 years ago
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