<h2>
8, 12, 16,...</h2><h2>
Find the 31st term.</h2><h3>352</h3>
<em>Hope I helped. :)</em>
<em />
<em>- Valenteer</em>
Its B just took the test the answer is B
Answer:
20.6
Step-by-step explanation:
Given data
J(-1, 5)
K(4, 5), and
L(4, -2)
Required
The perimeter of the traingle
Let us find the distance between the vertices
J(-1, 5) amd
K(4, 5)
The expression for the distance between two coordinates is given as
d=√((x_2-x_1)²+(y_2-y_1)²)
substitute
d=√((4+1)²+(5-5)²)
d=√5²
d= √25
d= 5
Let us find the distance between the vertices
K(4, 5), and
L(4, -2)
The expression for the distance between two coordinates is given as
d=√((x_2-x_1)²+(y_2-y_1)²)
substitute
d=√((4-4)²+(-2-5)²)
d=√-7²
d= √49
d= 7
Let us find the distance between the vertices
L(4, -2) and
J(-1, 5)
The expression for the distance between two coordinates is given as
d=√((x_2-x_1)²+(y_2-y_1)²)
substitute
d=√((-1-4)²+(5+2)²)
d=√-5²+7²
d= √25+49
d= √74
d=8.6
Hence the total length of the triangle is
=5+7+8.6
=20.6
Answer:
Step-by-step explanation:
d(x)=√((x-2)2+(y-0)²)
=√((x-2)²+y²)
=√((x-2)²+(x-1)²)
=√(x²-4x+4+x²-2x+1)
=√(2x²-6x+5)
D=d²(x)=2x²-6x+5
