Suppose that a dominant allele (P) codes for a polka-dot tail and a recessive allele (p) codes for a solid colored tail. If two

Question

3 years ago

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Suppose that a dominant allele (P) codes for a polka-dot tail and a recessive allele (p) codes for a solid colored tail. If two

heterozygous individuals with polka-dot tails mate, what's the probability of the phenotype and genotype combinations of the offspring? A. 25 percent chance of a polka-dot tail and 75 percent chance of a solid colored tail (25 percent PP; 50 percent Pp; 25 percent pp) B. 50 percent chance of a polka-dot tail and 50 percent chance of a solid colored tail (50 percent PP; 50 percent pp) C. 75 percent chance of a polka-dot tail and 25 percent chance of a solid colored tail (75 percent Pp; 25 percent pp) D. 75 percent chance of a polka-dot tail and 25 percent chance of a solid colored tail (25 percent PP; 50 percent Pp; 25 percent pp)

Biology

1 answer:

Butoxors [25] · Answer 1 · 2022-07-11T21:50:13+03:00

Butoxors [25]3 years ago

7 0

The answer is D. This is illustrated in the attached punnet square . There 25% homozygous dominant and the 50% heterozygous will have a polka-dot ponytail phenotype. The 25% homozygous recessive will have a solid color tail. Therefore the phenotypic ration is 3:1 (75%:25%).