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3 years ago

8

Factoring review. factor the following polynomials by determining a gcf. 21x-15y

1 answer:

butalik [34]3 years ago

3 0

The GCF of 21 and 15 is 3. The are no variables in common so the factor =
3(7x -5y)

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12a^2*b^4-36a^2*b+44abc

spayn [35]

Let's simplify step-by-step.

$12a^2*b^4-36a^2*b+44abc=$

There are no like terms.

Answer:

$12a^2*b^4-36a^2*b+44abc=$

5 0

2 years ago

Which lines have a y-intercept at (0,4)?

Sati [7]

Answer:

y=-3x+4

Step-by-step explanation:

Using the formula y=mx+b

mx= slope b= y-intercept

hence,

y=-3x+4 has a y-intercept of (0,4)

8 0

3 years ago

Read 2 more answers

A number divided by eleven.

Sliva [168]

Answer:

Take the alternating sum of the digits in the number, read from left to right. If that is divisible by 11, so is the original number. So, for instance, 2728 has alternating sum of digits 2 – 7 + 2 – 8 = -11. Since -11 is divisible by 11, so is 2728.

4 0

3 years ago

Which equation has a graph that passes through the points at (0,5) and (-3,-4)?

Roman55 [17]

Answer:

$y = 3x + 5$

Step-by-step explanation:

We are asked the equation of the graph which passes through the points at (0,5) and (-3,-4).

Now, we know that the equation of a straight line passing through the points ( $x_{1},y_{1}$ ) and ( $x_{2},y_{2}$ ) is given by

$\frac{y - y_{1}}{y_{1} - y_{2}} = \frac{x - x_{1}}{x_{1} - x_{2}}$ .

So, in our case ( $x_{1},y_{1}$ ) ≡ (0,5) and ( $x_{2},y_{2}$ ) ≡ (-3,-4)

Therefore, the equation of the straight line will be

$\frac{y - 5}{5 - (- 4)} = \frac{x - 0}{0 - (- 3)}$

⇒ $y - 5 = \frac{9}{3}x$

⇒ $y = 3x + 5$ (Answer)

4 0

3 years ago

Choose the option that best answers the question.The points A(0, 0), B(0, 4a – 5) and C(2a + 1, 2a + 6) form a triangle. If Angl

Sunny_sXe [5.5K]

Answer:

The correct option is 1.

Step-by-step explanation:

Given information: The coordinates of a right angled triangle ABC are A(0, 0), B(0, 4a – 5) and C(2a + 1, 2a + 6). Angle ABC = 90°.

It means AB and BC are legs of the right angled triangle ABC.

Side AB lies on the y-axis because the x-coordinate of both A and B is 0.

Two legs are perpendicular to each other. So, BC must be parallel to x-axis and the y-coordinate of both B and C is must be same.

$4a-5=2a+6$

$4a-2a=5+6$

$2a=11$

Divide both sides by 2.

$a=\frac{11}{2}$

The value of a is 2. So the coordinates of triangle ABC are

$B(0,4a-5)=B(0,4(\frac{11}{2})-5)\Rightarrow B(0,17)$

$C(2a+1,2a+6)=C(2(\frac{11}{2})+1,2(\frac{11}{2})+6)\Rightarrow C(12,17)$

The area of a triangle is

$Area=\frac{1}{2}|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|$

The area of triangle ABC is

$Area=\frac{1}{2}|0(17-17)+0(17-0)+12(0-17)|$

$Area=\frac{1}{2}|12(-17)|$

$Area=\frac{1}{2}|-204|$

$Area=\frac{1}{2}(204)$

$Area=102$

The area of triangle ABC is 102. Therefore the correct option is 1.

6 0

3 years ago