It has 1 solution i believe
There are 720 ways through which 3 numbers can be selected from 10 numbers to open a keypad lock.
Given that there are 10 numbers are 3 numbers are required to open a keypad lock.
Permutations are the number of ways in which objects can be selected without replacements to form subsets.
It is expressed as n
=n!/(n-r)!.
Factorial of a number is the product of consecutive numbers less than the number.
Total numbers available=10
Numbers to be selected=3
Number of ways can be found by using permutations.
Number of ways =10
=10!/(10-3)!
=10!/7!
=10*9*8*7!/7!
=10*9*8
=720 ways.
Hence there are 720 ways through which 3 numbers can be selected from 10 numbers.
Learn more about permutations at brainly.com/question/1216161
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None of these are true roots.
a. The closest true root to √50 is 7.
7^2 = 49
b. The closest true root to √150 is 12.
12^2 = 144
c. The closest true root to √350 is 19.
19^2 = 361
d. This is a cubed root, rather than a square root.
The closest root to 3√350 is 7.
7^3 = 343