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777dan777 [17]
3 years ago
12

If f(x) = 2x + 3 and g(x) = x2 + 1,find f(g(3)). 23 47 82 90

Mathematics
1 answer:
NISA [10]3 years ago
4 0
Hi!

So, this is going to be a function composition problem.

How we solve this, is by solving the function g(x). The output value we receive from solving g(x), is then the value that we input into the function f(x). 

So if g(x) equals something like 2, then we will input 2 into the function f(x).

Let's go ahead and solve g(3).

g(3) = 3^2 + 1.

First, we must solve the exponent due to the order of operations.

g(3) = 9 + 1.

Now we simply add 9 and 1.

g(3) = 10.

Okay, so - g(3) is equal to 10. Now we will input this value into f(x)!

f(10) = 2(10) + 3.

Again, we must follow the order of operations - so we will multiply 2 and 10 first.

f(10) = 20 + 3.

Now we add 20 and 3.

f(10) = 23.

Our final answer for this composite function is 23!

Hopefully, this helps! =)
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HELP PLEASE!! TON OF POINTS. RIGHT ANSWERS ONLY REWARDED. MATH GENIUSES?
Nonamiya [84]

Answer:

The graph is shifted 1 unit right

The graph is shifted 2 units down

Step-by-step explanation:

We are given

Parent function as

f(x)=2^{x+3}-3

New function as

g(x)=2^{x+2}-1

we can also write as

g(x)=2^{x+3-1}-3+2

We can see that

1 is subtracted to x-value

and 2 is added to y-value

So, f(x) is shifted right by 1 unit

and

f(x) is shifted up by 2 unit


3 0
3 years ago
18 of the last 30 cars that passed by you were black. what is the probability the next car will be black. (0.18, 0.6, or 0.30)
Black_prince [1.1K]
18 divided by 30 is 0.6. So I would say that B, or 0.6, is the correct answer.
3 0
3 years ago
Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu
olchik [2.2K]

Answer:

a) s^2 =30^2 =900

b) \frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

c) 23.818 \leq \sigma \leq 41.112

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in  the variability in the number of rooms occupied per day during a particular season of the  year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per  day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

s^2 =30^2 =900

Part b

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The degrees of freedom are given by:

df=n-1=20-1=19

Since the Confidence is 0.90 or 90%, the significance \alpha=0.1 and \alpha/2 =0.05, the critical values for this case are:

\chi^2_{\alpha/2}=30.144

\chi^2_{1- \alpha/2}=10.117

And replacing into the formula for the interval we got:

\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

Part c

Now we just take square root on both sides of the interval and we got:

23.818 \leq \sigma \leq 41.112

5 0
3 years ago
the perimeter of a rectangular field is (16a+8b-6c) units and one of its side is (5a+3b-4c) find the other side
Jet001 [13]

3a+b+c


The perimeter is two times one side (to account for the opposite) and two times the adjacent side. So if the sides would be x and y, the perimeter would be 2*x + 2*y.

So, knowing that the sum is 16a+8b-6c, if we subtract the given side 5a+3b-4c from this, what remains is two times the "other" side:

16a+8b-6c - 2*(5a+3b-4c) =

16a+8b-6c -10a-6b+8c =

6a+2b+2c

half of that is

(6a+2b+2c)/2 = 3a+b+c

7 0
3 years ago
Find the Distance between points A and B: A (8, 12) B: (2, 4)
mote1985 [20]
ANSWER-the distance is (6,8)
if you set the equation up from 2-8=6 which is your x value and 4-12=8 is your y value it should also give you your Distance between the two points
4 0
3 years ago
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