Given: 7r+3r-8=8+2r
Simplify: 10r-8=8+2r
Addition: add 8 to each side: 10r=16+2r
Subtraction: Take 2r from each side: 8r=16
Division: Divide each side by 8 for answer: r=2
Answer: r=2
(You go from left to right)
(Dividend is 931, divisor is 7)
Step 1: Look for a number smaller than 9 that is divisible by 7. 7 is the only one which is smaller than 9 and is divisible by 7. Now that you know 7*1=7, you put 1 above 931 (Dividend)
Step 2: You subtract that number from the number in tens place. And bring the leftover down.
Step 3: You repeat Step 1 and 2 until either you get a remainder of 0 or the remainder in smaller than the divisor (in this case 7)
(Therefore 931/7=133, quotient=133, remainder=0)
^Hope this helps.
= (16x3 - 8x2 + 4x4) / 2x
= 4x * (4x2 - 2x + x3) / 2x
= 2 * (4x2 - 2x + x3)
= 8x2 - 4x + 2x3
Answer A
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the answer is 10!!!!!!
good luck