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balandron [24]
2 years ago
8

Solve and i give brainliest

Mathematics
2 answers:
umka2103 [35]2 years ago
6 0

Answer:

1

Step-by-step explanation:

You're supposed to keep change flip the equation. Making the new equation -9/6 x -2/3 = 18/18

Temka [501]2 years ago
4 0

Answer:

0.25

Step-by-step explanation:

-9/6 divided by 3/-2 = 0.25

i am sorry

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Which expressions are equivalent to this exponential expression
stiks02 [169]

Answer:

c&b

5 {}^{(2 \times  (- 3 ))+ 4 + 4}

5^2

=25

8 0
3 years ago
Maci and I are making a small kite. Two sides are 10". Two sides are 5". The shorter diagonal is 6". Round all your answers to t
Art [367]

Answer:

A. 4".

B. Approximately 9.54".

C. Approximately 13.54".

Step-by-step explanation:

Please find the attachment.

Let x be the distance from the peak of the kite to the intersection of the diagonals and y be the distance from the peak of the kite to the intersection of the diagonals.

We have been given that two sides of a kite are 10 inches and two sides are 5 inches. The shorter diagonal is 6 inches.

A. Since we know that the diagonals of a kite are perpendicular and one diagonal (the main diagonal) is the perpendicular bisector of the shorter diagonal.

We can see from our attachment that point O is the intersection of both diagonals. In triangle AOD the side length AD will be hypotenuse and side length DO will be one leg.

We can find the value of x using Pythagorean theorem as:

(AO)^2=(AD)^2-(DO)^2

x^{2}=5^2-3^2

x^{2}=25-9

x^{2}=16

Upon taking square root of both sides of our equation we will get,

x=\sqrt{16}

x=\pm 4

Since distance can not be negative, therefore, the distance from the peak of the kite to the intersection of the diagonals is 4 inches.

B. We can see from our attachment that point O is the intersection of both diagonals. In triangle DOC the side length DC will be hypotenuse and side length DO will be one leg.

We can find the value of y using Pythagorean theorem as:

(OC)^2=(DC)^2-(DO)^2

Upon substituting our given values we will get,

y^2=10^2-3^2

y^2=100-9

y^2=91

Upon taking square root of both sides of our equation we will get,

y=\sqrt{91}

y\pm 9.539392

y\pm\approx 9.54

Since distance can not be negative, therefore, the distance from intersection of the diagonals to the top of the tail is approximately 9.54 inches.

C. We can see from our diagram that the length of longer diagram will be the sum of x and y.

\text{The length of the longer diagonal}=x+y

\text{The length of the longer diagonal}=4+9.54

\text{The length of the longer diagonal}=13.54

Therefore, the length of longer diagonal is approximately 13.54 inches.

3 0
3 years ago
Do you like forgs???
just olya [345]

Answer:

there ok

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Which of the following expressions are equivalent to \left(9\dfrac{7}{8} + 2\dfrac{4}{5}\right)-\dfrac{1}{2}(9 87​ +2 54​ )− 21​
lora16 [44]

Answer:

12\dfrac{7}{40}

Step-by-step explanation:

The given expression is

\left(9\dfrac{7}{8} + 2\dfrac{4}{5}\right)-\dfrac{1}{2}

We need to find the simplified form of the given expression.

It can be rewritten as

\left(9+\dfrac{7}{8} + 2+\dfrac{4}{5}\right)-\dfrac{1}{2}

Combine integers and fractions separately.

(9+2)+(\dfrac{7}{8}+\dfrac{4}{5}-\dfrac{1}{2})

Taking LCM we get

11+\dfrac{35+32-20}{40}

11+\dfrac{47}{40}

In can be written as

11+\dfrac{40+7}{40}

11+1+\dfrac{7}{40}

12+\dfrac{7}{40}

12\dfrac{7}{40}

Therefore, the expression 12\dfrac{7}{40} is equivalent to the given expression.

5 0
3 years ago
The difference of two numbers is equal to 0.6. Their quotient is also 0.6. What are the numbers? There are 4
Makovka662 [10]
Let the two numbers be represented by x and y. The problem statement gives rise to two sets of equations.
  x - y = 0.6
  y/x = 0.6 . . . . . . . assuming x is the larger of the two numbers
or
  x/y = 0.6 . . . . . . . assuming y has the larger magnitude

The solution of the first pair of equations is
  (x, y) = (1.5, 0.9)

The solution of the first and last equations is
  (x, y) = (-0.9, -1.5)

The pairs of numbers could be {0.9, 1.5} or {-1.5, -0.9}.
8 0
3 years ago
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