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PolarNik [594]
3 years ago
5

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Mathematics
1 answer:
son4ous [18]3 years ago
4 0

Answer:  a & b

<u>Step-by-step explanation:</u>

The sum of the probabilities should equal 1.0

a) <u>probability of 5/3 is greater than 1</u> shows that the probability distributions will result in a sum greater than 1.    

b) <u>The sum of the probabilities is 31/12</u> shows that the sum of the probability distributions is unequal to 1.0.

c) <u>The result is less than 0</u> is irrelevant.  The data could be temperature <em>(or something else which can be measured as a negative value).</em>

d) <u>The probabilities have different denominators</u> is irrelevant. Fractions can be reduced and unlike denominators can be turned into like denominators.  The most important thing is that their sum is 1.0.

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Answer:

Distance from the airport = 894.43 km

Step-by-step explanation:

Displacement and Velocity

The velocity of an object assumed as constant in time can be computed as

\displaystyle \vec{v}=\frac{\vec{x}}{t}

Where \vec x is the displacement. Both the velocity and displacement are vectors. The displacement can be computed from the above relation as

\displaystyle \vec{x}=\vec{v}.t

The plane goes at 400 Km/h on a course of 120° for 2 hours. We can compute the components of the velocity as

\displaystyle \vec{v_1}=

\displaystyle \vec{v_1}=\ km/h

The displacement of the plane in 2 hours is

\displaystyle \vec{x_1}=\vec{v_1}.t_1=.(2)

\displaystyle \vec{x_1}=km

Now the plane keeps the same speed but now its course is 210° for 1 hour. The components of the velocity are

\displaystyle \vec{v_2}=

\displaystyle \vec{v_2}=km/h

The displacement in 1 hour is

\displaystyle \vec{x_2}=\vec{v_2}.t_2=.(1)

\displaystyle \vec{x_2}=km

The total displacement is the vector sum of both

\displaystyle \vec{x_t}=\vec{x_1}+\vec{x_2}=+

\displaystyle \vec{x_t}=km

\displaystyle \vec{x_t}=

The distance from the airport is the module of the displacement:

\displaystyle |\vec{x_t}|=\sqrt{(-746.41)^2+492.82^2}

\displaystyle |\vec{x_t}|=894.43\ km

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Answer:

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A submarine starts at sea level and travels to a position that is a little lower than −24 feet. Use the drop-down menus to compl
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Answer:

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