All categories

3 years ago

PLEASE HELP ASAP !!!!! What would these be in scientific notation ?

Mathematics

1 answer:

Zarrin [17]3 years ago

4 0

$\text{the scientific notation}\\\\a\cdot10^n\ \text{where}\ 1\leq a < 10\ \text{and}\ n\in\mathbb{Z}$

$5\underbrace{7,909,000}_{\leftarrow7}km=5.7909\cdot10^7km\\\\1\underbrace{08,200,000}_{\leftarrow8}km=1.082\cdot10^8km\\\\1\underbrace{49,600,000}_{\leftarrow8}km=1.496\cdot10^8km\\\\2\underbrace{27,940,000}_{\leftarrow8}km=2.2794\cdot10^8km\\7\underbrace{78,330,000}_{\leftarrow8}km=7.7833\cdot10^8km\\\\1,\underbrace{424,600,000}_{\leftarrow9}km=1.4246\cdot10^9km\\\\4,\underbrace{498,252,900}_{\leftarrow9}km=4.4982529\cdot10^9km$

You might be interested in

HELP ME PLEASE I NEEED THIS <33

solong [7]

Since angle COB is the central angle of arc CB, the measure of arc CB = 80 degrees

5 0

3 years ago

1/9,1/3,5/9 find the rule

anastassius [24]

It’s going up by 2/9 . if you did it for the first one it’d b 3/9 which is 1/3

3 0

3 years ago

How did he get this 1/2i ? I dont remember studying this definition in calc 1 neither calc 2!

Hitman42 [59]

The $i$ in the denominator is missing in the second expression. It should be

$\sin at=\dfrac{e^{iat}-e^{-iat}}{2i}$

This follows from

$e^{iat}=\cos at+i\sin at$
$e^{-iat}=\cos at-i\sin at$
$\implies e^{iat}-e^{-iat}=2i\sin at$
$\implies \sin at=\dfrac{e^{iat}-e^{-iat}}{2i}$

8 0

3 years ago

the perimeter of the flag is 2340 ft. what is the flags width and length if the length is 330 ft. greater than the width

GalinKa [24]

Answer:

width=1005 length=1335

Step-by-step explanation:

If the length is 330 ft greater than you would subtract 330 from 2340 and then divide 2010 by 2 to get 1005 then add 330 to 1005 and get 1335

8 0

3 years ago

Animals were trapped in a city and later released into the wild. A random sample of the data is provided in the table below.

Fynjy0 [20]

Answer:

1,400

Step-by-step explanation:

We take the sample proportion of skunks and estimate for the entire population.

Sample:

140 skunks out of 230 + 140 + 120 = 490 animals.

140/490 = 0.28571428571

If a random sample of 5,000 animals are trapped in the city, how many skunks would be estimated to be included?

0.28571428571 out of 5000. So

0.28571428571*5000 = 1429

Close to 1400, which means that the answer is given by option C.

6 0

2 years ago