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Mamont248 [21]
3 years ago
15

A recipe calls for 3/4 cup of butter. Angie wants to triple the recipe, but she has only 1 5/8.

Mathematics
1 answer:
Lyrx [107]3 years ago
7 0
Let's start out by tripling the original recipe to see how much butter Angie needs.

\frac{3}{4} * 3 = total
\frac{3* 3}{4} = total
\frac{9}{4} = total
2 \frac{1}{4} = total

So we need 2 \frac{1}{4} cups of butter, but Angie only has 1 \frac{5}{8}. Let's subtract what Angie has from the total to see how much more she needs.

2 \frac{1}{4}  -  1\frac{5}{8} = n
\frac{9}{4} - \frac{13}{8} = n
we will need the least common denominator for both fractions
\frac{2}{2} *(\frac{9}{4}) - \frac{13}{8} = n
\frac{18}{8} - \frac{13}{8} = n
\frac{5}{8} = n

So Angie need \frac{5}{8} cups more of butter for the recipe.

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Answer:

Hey there!

Let's solve our equation below.

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Let's distribute the parentheses.

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We combine like terms.

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I hope this helps!

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borishaifa [10]

Answer:

y = 3x + 2

There slope is  3 and intercept is 2.

<u>First find what are the 2 pair that given by slope =3</u>

First consider A. (3, 11)  and B. (3, 9)

Tan α = \fraction(11-9)(3-3)

It is undefine.

Next consider A. (3, 11)  and BC (5,15)

Tan α = \fraction(15-11)(5-3)

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Next consider A. (3, 11)  and D. (2,4)

Tan α = \fraction(11-4)(3-2)

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Next consider B (3, 9)  and C. (5,15)

Tan α = \fraction(15-9)(5-3)

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Step-by-step explanation:

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Find the vertex of the given quadratic function.
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B

given f(x) in factored form, equate to zero for x-intercepts

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The vertex lies on the axis of symmetry which is situated at the midpoint of the x- intercepts

x- coordinate of vertex = \frac{4+8}{2} = 6

f(6) = (6 - 8 )(6 - 4 ) = -2 × 2 = - 4 ← y-coordinate

vertex = (6, - 4 ) → B




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