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julsineya [31]
3 years ago
8

Mary pumped 7 gallons of water out of her pool each minute for 63 minutes. What was the total change in the amount of water in t

he pool?
Mathematics
2 answers:
Marina CMI [18]3 years ago
6 0

Answer:

The pool has lost 441 gallons of water

Step-by-step explanation:

Multiply 7 (gallons last per minute) to 63 (the total amount of minutes) and you will get 441 gallons lost in total.

ruslelena [56]3 years ago
5 0

Answer:

The amount of water is 30 gallons a minute

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Alright here it is:

-2/7x + y = -7
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What are the rate of changes for
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3 years ago
Calculate two iterations of Newton's Method for the function using the given initial guess. (Round your answers to four decimal
pickupchik [31]

Answer:

The first and second iteration of Newton's Method are 3 and \frac{11}{6}.

Step-by-step explanation:

The Newton's Method is a multi-step numerical method for continuous diffentiable function of the form f(x) = 0 based on the following formula:

x_{i+1} = x_{i} -\frac{f(x_{i})}{f'(x_{i})}

Where:

x_{i} - i-th Approximation, dimensionless.

x_{i+1} - (i+1)-th Approximation, dimensionless.

f(x_{i}) - Function evaluated at i-th Approximation, dimensionless.

f'(x_{i}) - First derivative evaluated at (i+1)-th Approximation, dimensionless.

Let be f(x) = x^{2}-8 and f'(x) = 2\cdot x, the resultant expression is:

x_{i+1} = x_{i} -\frac{x_{i}^{2}-8}{2\cdot x_{i}}

First iteration: (x_{1} = 2)

x_{2} = 2-\frac{2^{2}-8}{2\cdot (2)}

x_{2} = 2 + \frac{4}{4}

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Second iteration: (x_{2} = 3)

x_{3} = 3-\frac{3^{2}-8}{2\cdot (3)}

x_{3} = 2 - \frac{1}{6}

x_{3} = \frac{11}{6}

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3 years ago
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Answer:

88

Step-by-step explanation:

I am 99.999% sure its the answer. You will get it right.

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