Complete question :
Mr. Nelson lost one of his students' test papers. He knows that the other 4 students scored as follows: 60, 62, 56, 57. He also knows that the average score is 59.2. What is the score on the missing paper?
Answer:
61
Step-by-step explanation:
Given the following :
Total number of students = 4 + 1 missing = 5
Score on the four avaliable papers = 60, 62, 56, 57
Average score of the 5 papers = 59.2
Score on missing paper :
Sum of each score / number of papers
Sum of each score = sum of available scores + missing score
Let missing score = m
(60 + 62 + 56 + 57 + m) = 235 + m
Recall:
Average = total sum / number of observations
Hence,
59.2 = (235 + m) / 5
59.2 × 5 = 235 + m
296 = 235 + m
m = 296 - 235
m = 61
Missing score = 61
The three integers are: 12, 13, and 14
12+13=25
25+14=39
-2(-53)×36-24-36 》3816-60=3756
<h3>
Answer is 4:5</h3>
========================================================
Explanation:
She saved 10 shots out of 18 total, so that means 18-10 = 8 shots went in.
That forms the ratio 8:10 where we list the amount of shots that went in, followed by a colon, then the amount of shots that were saved. The order is important. From here, we divide both parts of the ratio by 2. The ratio 8:10 fully reduces to 4:5
Effectively, this means that for every 4 shots that went in, there were 5 shots that were blocked.
12/10, 1.2, and any of the infinite multiples of the fraction such as 24/20, 120/100 etc...
