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Free_Kalibri [48]
3 years ago
12

Which of the following is a narrative essay most like

Computers and Technology
2 answers:
cluponka [151]3 years ago
8 0
The answer to your question is it's most like a story. I hope that answered your question, my friend. :)
Nataliya [291]3 years ago
4 0
The answer if defiantly B. Story

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If you would like to give another user permissions on your mailbox or to particular folders within your mailbox, which role shou
olga2289 [7]

Answer:

assignee

Explanation:

5 0
3 years ago
write a c++program that allows the user to enter the last names of fivecandidates in a local election and the number of votes re
madreJ [45]

Answer:

#include<iostream>

#include<stdlib.h>

using namespace std;

int main(){

   //initialization

   string str1[5];

   int arr_Vote[5];

   int Total_Vote=0,max1_Index;

   int max1=INT_MIN;

   //loop for storing input enter by user

   for(int i=0;i<5;i++){

       cout<<"Enter the last name of candidate: "<<endl;

       cin>>str1[i];

       cout<<"Enter the number of vote receive by the candidate: "<<endl;

       cin>>arr_Vote[i];

       //calculate the sum

       Total_Vote = Total_Vote + arr_Vote[i];

       //find the index of maximum vote

       if(arr_Vote[i]>max1){

           max1=arr_Vote[i];

           max1_Index=i;

       }

   }

   //display

   cout<<"\nThe output is......"<<endl;

   //loop for display data of each candidate

   for(int i=0;i<5;i++){

       cout<<str1[i]<<"\t"<<arr_Vote[i]<<"\t"     <<float(arr_Vote[i]*100)/Total_Vote<<"%"<<endl;

   }

   //display winner

   cout<<"The winner candidate is"<<endl;

   cout<<str1[max1_Index]<<"\t"<<arr_Vote[max1_Index]<<"\t"<<float(arr_Vote[max1_Index]*100)/Total_Vote<<" %"<<endl;

}

Explanation:

Create the main function and declare the two arrays and variables.

the first array for storing the names, so it must be a string type. second array stores the votes, so it must be int type.

after that, take a for loop and it runs for 5 times and storing the values entered by the user in the arrays.

we also calculate the sum by adding the array data one by one.

In the same loop, we also find the index of the maximum vote. take an if statement and it checks the element in the array is greater than the max1 variable. Max1 variable contains the very small value INT_MIN.

If condition true, update the max1 value and update the max1_Index value.

The above process continues for each candidate for 5 times.

After that, take a for loop and display the data along with percentage by using the formula:

Vote\,percent=\frac{Vote\,receive*100}{Total\,vote}

the, finally display the winner by using the max1_Index value.  

5 0
3 years ago
Q2
rosijanka [135]

Answer:

Computer is a electronic device which give us accurate result in a short preodical of time

6 0
2 years ago
Read 2 more answers
Your app needs to store the following information. For each type of information, decide whether you would use an array or a vari
Virty [35]

Answer:

Array: (a) All the messages a user has sent.

Variable: (b) The highest score a use has reached on the app. (c) A username and password to unlock the app.

Explanation:

An array generally has more than one value whereas a variable can only contain a single value at any particular point in time. In addition, a variable has a limit whereas an array does not have any maximum limit. Therefore, it can be concluded that option (a) will be stored as an array while options (b) and (c) will be stored as variables.

3 0
3 years ago
Write a program that reads whitespace delimited strings (words) and an integer (freq). Then, the program outputs the strings fro
Lesechka [4]

Answer:

See explaination for the code

Explanation:

def wordsOfFrequency(words, freq):

d = {}

res = []

for i in range(len(words)):

if(words[i].lower() in d):

d[words[i].lower()] = d[words[i].lower()] + 1

else:

d[words[i].lower()] = 1

for word in words:

if d[word.lower()]==freq:

res.append(word)

return res

Note:

First a dictionary is created to keep the count of the lowercase form of each word.

Then, using another for loop, each word count is matched with the freq, if it matches, the word is appended to the result list res.

Finally the res list is appended.

3 0
3 years ago
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