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ruslelena [56]
4 years ago
8

What is the square root of 24

Mathematics
1 answer:
nata0808 [166]4 years ago
5 0

Answer:

4.898

Step-by-step explanation:


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Solve this system of equations using the addition method.<br> 5x + 2y = 19<br> x - 2y = -1
Elena-2011 [213]
2y+5x-5x= 19-5x. x-x-2y=-1-x
2y= 19-5x. -2y=-1-x
÷2= ÷2. ÷-2 = ÷-2
y= 19/2 -5/2x. Y = 1/2 + x/2
8 0
3 years ago
Find an equation of the circle that has center (-6, 6) and passes through (3,-4)​
daser333 [38]

Answer:

(x+6)² + (y-6)² = 181

Step-by-step explanation:

equation of the circle in general is (x - a)² + (y - b)² = r²

center is (a, b) in our task a=-6 b=6

so equation of the circle is (x+6)² + (y-6)² = r²

we have point  (3,-4)​ ⇒ x=3 y=-4

put x y in equation of the circle ⇒  (3+6)² + (-4-6)² = r² ⇒r² =181

⇒The equation of a circle is (x+6)² + (y-6)² = 181

4 0
3 years ago
Read 2 more answers
Please help extra points and Mark brainlist
jenyasd209 [6]

Answer:

Same

Step-by-step explanation:

4 0
3 years ago
You are running a concession stand at a basketball game. You are selling hot dogs and sodas. Each hot dog costs $1.50 and each s
DochEvi [55]

Answer:

<u>x= 35 hot dogs</u>

<u>y= 52 soda</u>

Step-by-step explanation:

x= hot dogs

y= soda

Total sold

1 x + 1 y = 87 .............1

2 x 0.50 y = 78.50 .............2

Eliminate y

multiply (1)by -0.50

Multiply (2) by 1.00

-0.50 x -0.50 y = -43.50

2 x + 0.50 y = 78.50

Add the two equations

1 x = 35.00

/ 1

x = 35.00

plug value of x in (1)

1 x + 1 y = 87

35 + y = 87

y = 87 -35

y = 52

y = 52.00

x= 35 hot dogs

y= 52 soda

6 0
3 years ago
If a wheel has a diameter of 15 centimeters what is the area of the wheel nearest centimeter
maw [93]

Answer:

<h2>A = 177 cm²</h2>

Step-by-step explanation:

A diameter is two times longer than a radius. Therefore, if the diameter

d = 15cm, then the radius r = (15cm) : 2 = 7.5cm.

The formula of an area of a circle:

A=\pi r^2

Substitute:

A=\pi(7.5)^2=56.25\pi\ cm^2

\pi\approx3.14

Then

A\approx(56.25)(3.14)\approx177\ cm^2

4 0
3 years ago
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