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Viefleur [7K]
3 years ago
15

How do I factor 6x^2+17x+5=0

Mathematics
2 answers:
dsp733 years ago
6 0

Answer:


Step-by-step explanation:

6x^2+17x+5=0

(3x+1)(2x+5)=0

x = -1/3, x = -5/2

Sergio [31]3 years ago
3 0

Split the second term in 6x^2 + 17x + 5 into two terms

6x^2 + 15x + 2x + 5 = 0

Factor out common terms in the first two terms, then in the last two terms.

3x(2x + 5) + (2x + 5) = 0

Factor out the common term 2x + 5

(2x + 5)(3x + 1) = 0

Solve for x

<u>x = -5/2, -1/3</u>

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Answer:

  1. -√5
  2. 3/5
  3. -4/5

Step-by-step explanation:

The relevant relations are ...

  sec = ±√(tan² +1)

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Sine and Cosecant are positive in quadrants I and II. Cosine and Secant are positive in quadrants I and IV.

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1. sec(θ) = -√((-2)² +1) = -√5

2. cos(θ) = 1/sec(θ) = 1/(5/3) = 3/5

3. csc(θ) = -1/√(1 -(-3/5)²) = -√(16/25) = -4/5

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2 years ago
What line is parallel y=5x-3
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Show all work:<br> -13 +(-56): 14 +9=<br> -16•3 - (-36) /12 =
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3 years ago
Read 2 more answers
What is the solution to the equation √x^2+2x-25=√x+5 x = –6 x = 5 x = 6, x = –5 x = –6, x = 5
Dimas [21]

Answer:

x = 5, -6

Step-by-step explanation:

Step 1: Write out equation

x² + 2x - 25 = x + 5

Step 2: Move everything to one side

x² + x - 30 = 0

Step 3: Factor

(x - 5)(x + 6) = 0

Step 4: Find roots

x - 5 = 0

x = 5

x + 6 = 0

x = -6

4 0
3 years ago
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