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sasho [114]
3 years ago
7

On August 12, 2000, the Russian submarine Kursk sank to the bottom of the sea, 350 feet below the surface

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
7 0
A) The answer is 3,596,866.62 N

Step 1. Calculate the water pressure at the bottom of the ocean where the Kursk sank because: Force (F) = Pressure (P) * Area (A). P = ?
Step 2. Calculate the area (A) of <span>a 6 foot square</span> metal sheet: A = ?
Step 3. Calculate the <span>force on a 6 foot square metal sheet held horizontally at the depth of the Kursk: F = ?

Step 1. The </span>water pressure at the bottom of the ocean is:
P = ρ * g * h
ρ - the density of the sea water: ρ = 1,027 kg/m³
g - the gravitational acceleration: g = 9.8 m/s²
h - the height: h = 350 ft = 106.68 m
P = 1,027 * 9.8 * 106.68 = 1,073,691.53 kg/m*s²

Step 2. The area of a <span>6 foot square metal sheet is:
A = s</span>²
s - the side of the square: s = 6 ft = 1.83 m
A = (1.83 m)² = 3.35 m²

Step 3. T<span>he force on a 6 foot square metal sheet held horizontally at the depth of the Kursk is:
F = P * A
P = </span>1,073,691.53 kg/m*s²
A = 3.35 m²
F = 1,073,691.53 kg/m*s² * 3.35 m² = 3,596,866.62 N


b) The answer is 3,535,165.59 N.

Step 1. Calculate the water pressure at the bottom of the ocean where the Kursk sank because: Force (F) = Pressure (P) * Area (A). P = ?
Step 2. Calculate the area (A) of a 6 foot square metal sheet: A = ?
Step 3. Calculate the force on a 6 foot square metal sheet held horizontally at the depth of the Kursk: F = ?

Step 1. The water pressure at the bottom of the ocean is:
P = ρ * g * h
ρ - the density of the sea water: ρ = 1,027 kg/m³
g - the gravitational acceleration: g = 9.8 m/s²
h - the height: h = 350 ft - 6 ft = 344 ft (Since it is vertically held, the height of the metal sheet must be subtracted from the total depth)
h = 344 ft = 104.85 m= 104.85 m
P = 1,027 * 9.8 * 104.85 = 1,055,273.31 kg/m*s²

Step 2. The area of a 6 foot square metal sheet is:
A = s²
s - the side of the square: s = 6 ft = 1.83 m
A = (1.83 m)² = 3.35 m²

Step 3. The force on a 6 foot square metal sheet held horizontally at the depth of the Kursk is:
F = P * A
P = 1,055,273.31 kg/m*s²
A = 3.35 m²
F = 1,055,273.31 kg/m*s² * 3.35 m² = 3,535,165.59 N
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Outside:

(x√7 - 3√8 ) (x√7 - 3√8 )

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Now we have: -3x2√14 ---> -6x√14  

Inside:

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The process is the exact same as in the "outside"

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√56 can be further simplified to: 2√14

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Now combine all the products of the FOIL together like so...

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Combine like terms:

 

7x² - 6x√14 - 6x√14 + 72

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