Step 1. Calculate the water pressure at the bottom of the ocean where the Kursk sank because: Force (F) = Pressure (P) * Area (A). P = ? Step 2. Calculate the area (A) of <span>a 6 foot square</span> metal sheet: A = ? Step 3. Calculate the <span>force on a 6 foot square metal sheet held horizontally at the depth of the Kursk: F = ?
Step 1. The </span>water pressure at the bottom of the ocean is: P = ρ * g * h ρ - the density of the sea water: ρ = 1,027 kg/m³ g - the gravitational acceleration: g = 9.8 m/s² h - the height: h = 350 ft = 106.68 m P = 1,027 * 9.8 * 106.68 = 1,073,691.53 kg/m*s²
Step 2. The area of a <span>6 foot square metal sheet is: A = s</span>² s - the side of the square: s = 6 ft = 1.83 m A = (1.83 m)² = 3.35 m²
Step 3. T<span>he force on a 6 foot square metal sheet held horizontally at the depth of the Kursk is: F = P * A P = </span>1,073,691.53 kg/m*s² A = 3.35 m² F = 1,073,691.53 kg/m*s² * 3.35 m² = 3,596,866.62 N
b) The answer is 3,535,165.59 N.
Step 1. Calculate the water pressure at the bottom of the ocean where the Kursk sank because: Force (F) = Pressure (P) * Area (A). P = ? Step 2. Calculate the area (A) of a 6 foot square metal sheet: A = ? Step 3. Calculate the force on a 6 foot square metal sheet held horizontally at the depth of the Kursk: F = ?
Step 1. The water pressure at the bottom of the ocean is: P = ρ * g * h ρ - the density of the sea water: ρ = 1,027 kg/m³ g - the gravitational acceleration: g = 9.8 m/s² h - the height: h = 350 ft - 6 ft = 344 ft (Since it is vertically held, the height of the metal sheet must be subtracted from the total depth) h = 344 ft = 104.85 m= 104.85 m P = 1,027 * 9.8 * 104.85 = 1,055,273.31 kg/m*s²
Step 2. The area of a 6 foot square metal sheet is: A = s² s - the side of the square: s = 6 ft = 1.83 m A = (1.83 m)² = 3.35 m²
Step 3. The force on a 6 foot square metal sheet held horizontally at the depth of the Kursk is: F = P * A P = 1,055,273.31 kg/m*s² A = 3.35 m² F = 1,055,273.31 kg/m*s² * 3.35 m² = 3,535,165.59 N
