Take the decimal and multiply it by 100.
Answer:
0.225 L of milk, would be
required if she uses 450 m L of water.
Step-by-step explanation:
Here, to make the shake, ingredients used by Dina are:
40 m L of chocolate syrup,
200 m L of milk, and 400 m L of water.
So, here Amount of water used = 2 x ( Amount of Milk used) ....... (1)
Now,again the amount of water used by Dona = 450 m L
Let us assume the milk used by her = k m L
⇒ 450 m L = 2 x ( k m L) ( from (1))
or, 450 = 2 k
⇒ k = 450/2 = 225
⇒ k = 225 m L
Also, 1 m L = 0.001 L
So, 225 m L = 225 x 0.001 = 0.225 L
⇒ k = 0.225 L
Hence, 0.225 L of milk, would be
required if she uses 450 m L of water.
Answer:
0.8041 = 80.41% probability that a given battery will last between 2.3 and 3.6 years
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
A certain type of storage battery lasts, on average, 3.0 years with a standard deviation of 0.5 year
This means that 
What is the probability that a given battery will last between 2.3 and 3.6 years?
This is the p-value of Z when X = 3.6 subtracted by the p-value of Z when X = 2.3. So
X = 3.6



has a p-value of 0.8849
X = 2.3



has a p-value of 0.0808
0.8849 - 0.0808 = 0.8041
0.8041 = 80.41% probability that a given battery will last between 2.3 and 3.6 years